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olga_2 [115]
4 years ago
9

elise is changing the dimensions of her garden. the length is 20 feet longer than its width. if she decreases this length by 8 f

eet and increases the width by 10 feet, the perimeter will be 172 feet. what are the original dimensions of the garden? what will be the new dimensions of the garden?
Mathematics
1 answer:
vitfil [10]4 years ago
4 0
Let x be the initial width, then the initial length is x+20.
<span>If Elise decreases this length by 8 feet, she will get the new length  x+20-8=x+12.
</span>
 If Elise increases the width by 10 feet, <span>she will get the new width x+10.
</span><span>
</span><span>The new perimeter will be x+12+x+12+x+10+x+10=4x+44=172, 4x=172-44, 4x=128,  x=128÷4, x=32.
</span><span>
</span><span>The initial width is 32 ft and the initial length is 32+20=52 ft.
</span><span>
</span><span>The new width will be 32+10=42 ft, the new length will be 32+12=44 ft.
</span>




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Gnesinka [82]

Answer:

x<6/5, x>14/5

Step-by-step explanation:

Steps

$5\left|x-2\right|+4>8$

$\mathrm{Subtract\:}4\mathrm{\:from\:both\:sides}$

$5\left|x-2\right|+4-4>8-4$

$\mathrm{Simplify}$

$5\left|x-2\right|>4$

$\mathrm{Divide\:both\:sides\:by\:}5$

$\frac{5\left|x-2\right|}{5}>\frac{4}{5}$

$\mathrm{Simplify}$

$\left|x-2\right|>\frac{4}{5}$

$\mathrm{Apply\:absolute\:rule}:\quad\mathrm{If}\:|u|\:>\:a,\:a>0\:\mathrm{then}\:u\:<\:-a\:\quad\mathrm{or}\quad\:u\:>\:a$

$x-2<-\frac{4}{5}\quad\mathrm{or}\quad\:x-2>\frac{4}{5}$

Show Steps

$x-2<-\frac{4}{5}\quad:\quad x<\frac{6}{5}$

Show Steps

$x-2>\frac{4}{5}\quad:\quad x>\frac{14}{5}$

$\mathrm{Combine\:the\:intervals}$

$x<\frac{6}{5}\quad\mathrm{or}\quad\:x>\frac{14}{5}$

5 0
3 years ago
Addy has 51.79 pounds of dirt. She has buckets in her garage. Each bucket can hold 2.5 pounds of dirt. If she has 20 buckets wil
kirill [66]

Answer:

No

Step-by-step explanation:

20x2.5=50

51.79-50=1.79

therefore there isn't enough buckets for all the dirt.

4 0
3 years ago
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Factor the trinomial<br><br> x^2-9x+4x
8090 [49]

Answer:


Step-by-step explanation:

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x2 + -9x = 4x + -4

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-9x + x2 = 4x + -4

Reorder the terms:

-9x + x2 = -4 + 4x

Solving

-9x + x2 = -4 + 4x

Solving for variable 'x'.

Reorder the terms:

4 + -9x + -4x + x2 = -4 + 4x + 4 + -4x

Combine like terms: -9x + -4x = -13x

4 + -13x + x2 = -4 + 4x + 4 + -4x

Reorder the terms:

4 + -13x + x2 = -4 + 4 + 4x + -4x

Combine like terms: -4 + 4 = 0

4 + -13x + x2 = 0 + 4x + -4x

4 + -13x + x2 = 4x + -4x

Combine like terms: 4x + -4x = 0

4 + -13x + x2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-4' to each side of the equation.

4 + -13x + -4 + x2 = 0 + -4

Reorder the terms:

4 + -4 + -13x + x2 = 0 + -4

Combine like terms: 4 + -4 = 0

0 + -13x + x2 = 0 + -4

-13x + x2 = 0 + -4

Combine like terms: 0 + -4 = -4

-13x + x2 = -4

The x term is -13x.  Take half its coefficient (-6.5).

Square it (42.25) and add it to both sides.

Add '42.25' to each side of the equation.

-13x + 42.25 + x2 = -4 + 42.25

Reorder the terms:

42.25 + -13x + x2 = -4 + 42.25

Combine like terms: -4 + 42.25 = 38.25

42.25 + -13x + x2 = 38.25

Factor a perfect square on the left side:

(x + -6.5)(x + -6.5) = 38.25

Calculate the square root of the right side: 6.184658438

Break this problem into two subproblems by setting  

(x + -6.5) equal to 6.184658438 and -6.184658438.


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3 years ago
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2. What is the effective annual rate of an investment that pays 6% for 5 years, compounded semiannually?
Ede4ka [16]

Answer:

effective annual rate is 6.16 %

Step-by-step explanation:

given data

rate = 6 % = 0.06

time 5 year = 10 semi annually

to find out

effective annual rate

solution

we know formula for annual effective rate of interest is

rate of  interest = (1+ r/n)^{n} -1

put here all value

rate of interest = (1+ 0.06/10)^{10} -1

rate of  interest = (1+ 0.06/10)^{10} -1

rate of interest = 0.061646

so effective annual rate is 6.16 %

8 0
3 years ago
In 1982 Abby’s mother scored at the 93rd percentile in the math SAT exam. In 1982 the mean score was 503 and the variance of the
oksian1 [2.3K]

Answer:

The percentle for Abby's score was the 89.62nd percentile.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation(which is the square root of the variance) \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Abby's mom score:

93rd percentile in the math SAT exam. In 1982 the mean score was 503 and the variance of the scores was 9604.

93rd percentile. X when Z has a pvalue of 0.93. So X when Z = 1.476.

\mu = 503, \sigma = \sqrt{9604} = 98

So

Z = \frac{X - \mu}{\sigma}

1.476 = \frac{X - 503}{98}

X - 503 = 1.476*98

X = 648

Abby's score

She scored 648.

\mu = 521 \sigma = \sqrt{10201} = 101

So

Z = \frac{X - \mu}{\sigma}

Z = \frac{648 - 521}{101}

Z = 1.26

Z = 1.26 has a pvalue of 0.8962.

The percentle for Abby's score was the 89.62nd percentile.

3 0
3 years ago
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