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Murljashka [212]
3 years ago
6

A new computer system sells for approximately $2000 and depreciates at the rate of $500 per year.

Mathematics
1 answer:
lukranit [14]3 years ago
8 0

what are you asking

Step-by-step explanation:

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Hayden is building toy cars. Each car needs 4 wheels. How many wheels will Hayden use to build 3 toy cars?
ycow [4]

Answer:

12

Step-by-step explanation:

Three cars each need 4 wheels, so that is...

4 + 4 + 4 wheels, which is 12 wheels

8 0
3 years ago
Help please ::)))))........................
Zarrin [17]

Answer:

4:9

Step-by-step explanation:

  1. Circles: 8
  2. Total shapes: squares + circles
  3. Total shapes: 10 + 8
  4. Total shapes: 18
  5. Circles : Total shapes = 8:18
  6. 8:18 = 4:9

I hope this helps!

3 0
3 years ago
Read 2 more answers
Solve the system by substitution.<br> -2x + 7y = 15<br> бу = 3
Salsk061 [2.6K]

Answer:

Step-by-step explanation:

-2x + 7(1/2) =15

-4x +7 =30

-4x =23

x=-23/4

6 0
3 years ago
Consider the first month's sales data for the Midwest region.
myrzilka [38]

Answer:

1. Significantly different from

1. Inconsistent

Step-by-step explanation:

Midwest region total stores equal to 63.1%. The percentage for current store is less than total stores therefore data in the given table is not consistent. The data given is relatively for the first month sales and is significantly different from the other stores.

8 0
3 years ago
A telemarketer is successful at getting people to donate money for her organization in 55% of all calls she makes. She must get
Tems11 [23]
An interesting twist to a binomial distribution problem.

Given:
p=55%=0.55 for probability of success in solicitation
x=4=number of successful solicitations
n=number of calls to be made
P(x,n,p)>=89.9%=0.899  (from context, it is >= and not =, which is almost impossible)

From context of question, all calls are assumed independent, with constant probability of success, so binomial distribution is applicable.

The number of successes, x, is then given by
P(x)=C(n,x)p^x(1-p)^{n-x}where
p=probability of success
n=number of trials
x=number of successesC(n,x)=\frac{n!}{x!(n-x)!}

Here we need n such that
P(x,n,p)>=0.899
given
x>=4, p=0.55, which means we need to find

Method 1: if a cumulative binomial distribution table is available, we can look up n=9,10,11 and find
P(x>=4,9,0.55)=0.834
P(x>=4,10,0.55)=0.898
P(x>=4,11,0.55)=0.939
So she must make (at least) 11 calls to make sure the probability of meeting her quota is 89.9% or more.

Method 2: using technology.
Similar to method 1, we can look up the probabilities directly, for n=9,10,11
P(x>=4,9,0.55)=0.834178
P(x>=4,10,0.55)=0.8980051
P(x>=4,11,0.55)=0.9390368

Method 3: using simple calculator
Here we need to calculate the probabilities for each value of n=10,11 and sum the probabilities of FAILURE S=P(0,n,0.55)+P(1,n,0.55)+P(2,n,0.55)+P(3,n,0.55)
so that the probability of success is 1-S.
For n=10,
P(0,10,0.55)=0.000341
P(1,10,0.55)=0.004162
P(2,10,0.55)=0.022890
P(3,10,0.55)=0.074603
So that
S=0.000341+0.004162+0.022890+0.074603
=0.101995
and Probability of getting 4 successes (or more) 
=1-S
=0.898005, missing target by 0.1%

So she will have to make 11 phone calls, bring up the probability to 93.9%.  The work is similar to that of n=10.
8 0
3 years ago
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