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3 years ago

What is the product of −2 2/5 and −3 5/6 ?

Mathematics

2 answers:

masya89 [10]3 years ago

6 0

The answer is -5.12333333

MatroZZZ [7]3 years ago

5 0

9.2 or 9 1/5 is the correct answer.

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A concrete stepping-stone measures 20 square inches. What is the area of 30 such stones?

nasty-shy [4]

Just multiply 20 x 30 and you get 600 and that is your answer :3

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3 years ago

I give brainliest if the answer is correct

nirvana33 [79]

12000 > 3000+25x Or you can write it out as (12000-3000)/25=x

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2 years ago

How to do splitting method of x square- 2x -8

Leni [432]

Answer:

Hey mate

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3 years ago

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You are making juice from concentrate. The directions on the packaging say to mix

mel-nik [20]

Answer:

25 can.

Step-by-step explanation:

Here is the complete question: You are making juice from concentrate. The directions on the packaging say to mix 1 can of juice with 3 cans of water to make orange juice. How many 12 fluid ounces cans of the concentrate are required to prepare 200 6-ounce servings of orange juice?

Given: Ratio to make juice with concentrate:water is 1:3.

As required we need to prepare 200 6 ounce serving of Orange juice.

∴ $200\times 6= 1200\ ounce$

Let there be x ounce of concentrate and 3x ounce of water to make 1200 ounce of orange juice.

Now, $x+3x= 1200$

∴ x= 300 ounce

Next, lets find out how many cans of 12 ounce is required.

$\frac{300}{12} = 25\ cans$

∴ 25 cans is required to make 1200 ounce of orange juice.

3 0

3 years ago

Four lawn sprinkler heads are fed by a 1.9-cm-diameter pipe. The water comes out of the heads at an angle of 35° above the horiz

klemol [59]

Answer:

Step-by-step explanation:

Given:

Angle, θ = 35°

Vertical distance, Δx = 6 m

Diameter, d = 1.9 cm

= 0.019 m

When the water leaves the sprinkler, it does so at a projectile motion.

Therefore,

Using equation of motion,

(t × Vox) = 2Vo²(sin θ × cos θ)/g

= Δx = 2Vo²(sin 35 × cos 35)/g

Vo² = (6 × 9.8)/(2 × sin 35 × cos 35)

= 62.57

Vo = 7.91 m/s

Area of sprinkler, As = πD²/4

Diameter, D = 3 × 10^-3 m

As = π × (3 × 10^-3)²/4

= 7.069 × 10^-6 m²

V_ = volume rate of the sprinkler

= area, As × velocity, Vo

= (7.069 × 10^-6) × 7.91

= 5.59 × 10^-5 m³/s

Remember,

1 m³ = 1000 liters

= 5.59 × 10^-5 m³/s × 1000 liters/1 m³

= 5.59 × 10^-2 liters/s

= 0.0559 liters/s.

For the 4 sprinklers,

The rate at which volume is flowing in the 4 sprinklers = 4 × 0.0559

= 0.224 liters/s

Area of 1.9 cm pipe, Ap = πD²/4

= π × (0.019)²/4

= 2.84 × 10^-4 m²

Volumetric flowrate of the four sprinklers = 4 × 5.59 × 10^-5 m³/s

= 2.24 × 10^-4 m³/s

Velocity of the water, Vw = volumetric flowrate/area

= 2.24 × 10^-4/2.84 × 10^-4

= 0.787 m/s

7 0

3 years ago

Read 2 more answers