Answer:
#18) <em>m</em>∠B = 107°
#19) <em>m</em>∠B = 17°
Step-by-step explanation:
*Supplementary angles are angles who's measures equal 180°
*Complementary angles are angles who's measures equal 90°
#18) If ∠A is 73°, then we must subtract 73 from 180.
180 - 73 = 107
This means that <em>m</em>∠B = 107°.
#19) If ∠A is 73°, then we must subtract 73 from 90.
90 - 73 = 17
This means that <em>m</em>∠B = 17°.
Answer:
use Pythagoras theorem
the missing side is base
Step-by-step explanation:
pythagoras theorem
h^2 = p^2 + b^2
73^2 = 48^2 + b^2
5329 = 2304 + b^2
5329 - 2304 = b^2
3025 = b^2
√3025 = b
55 = b
Answer:

Step-by-step explanation:
We want to prove algebraically that:

is a parabola.
We use the relations

and

Before we substitute, let us rewrite the equation to get:

Or

Expand :

We now substitute to get:

This means that:

Square:

Expand:




This is a parabola (0,2.5) and turns upside down.
Answer:
a, y =3/x
x = 0.5 => y = 3/0.5 = 6
x = 1 => y = 3/1 = 3
x = 2 => y = 3/2 = 1.5
x = 3 => y = 3/3 = 1
x = 4 => y = 3/4 = 0.75
b,
y = 3/x passes (0.5, 6) => A is correct
Hope this helps!