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3 years ago

THIS IS VERY SIMPLE BUT I GET CONFUSED SOMETIMES LOL

Mathematics

2 answers:

Bogdan [553]3 years ago

7 0

Answer:

the answer is 24

Step-by-step explanation:

15-(-9)=24

Phantasy [73]3 years ago

7 0

Answer: -24°

15°-24°= -9°

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PLEZ HELP ASAP

lisov135 [29]

Answer:

a median

b center

Step-by-step explanation:

The middle value of a set of numbers is the median

The mean is the average value and the range is the largest minus the smallest.

This value is a measure of the center ( or a measure of the middle)

The range is a measure of the spread

8 0

3 years ago

Read 2 more answers

Using the quadratic formula to solve x2 + 20 = 2x, what are the values of x?

jeka94

by Quadratic formula , $x^2 + 20 = 2x$ , values of x are $x = 1 \pm (1)i\sqrt{19}}$ . None of mentioned options are correct according to question!

Step-by-step explanation:

Here we have , expression x2 + 20 = 2x or , $x^2 + 20 = 2x$ .

We know that Quadratic formula is :

$x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a}$

$x^2 + 20 = 2x$

⇒ $x^2-2x+20=0$

$a=1\\b=-2\\c=20$

Putting this value in equation $x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a}$ :

⇒ $x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a}$

⇒ $x = \frac{-(-2) \pm \sqrt{(-2)^{2}-4(1)(20)}}{2(1)}$

⇒ $x = \frac{2 \pm \sqrt{4-80}}{2}$

⇒ $x = (\frac{2 \pm 2i\sqrt{19}}{2})$

⇒ $x = 1 \pm (1)i\sqrt{19}}$

Therefore , by Quadratic formula , $x^2 + 20 = 2x$ , values of x are $x = 1 \pm (1)i\sqrt{19}}$ . None of mentioned options are correct according to question!

7 0

3 years ago

Got some easy questions, to do. Will give, Branliest. :)

Ivanshal [37]

1.)3

2.)6

3.)9

4.)12

5.)18

6.)?

7.)?

8 0

3 years ago

Read 2 more answers

Find the distance between the points of intersection of the graphs of the functions.

Viefleur [7K]

Answer:

Find the value of x and y in coordinate form, that'll be the point of intersection.

Question 1

${ \rm{y = {x}^{2} - 3x + 4 }} \\ { \boxed{ \tt{but \: y = x + 1 \: }}} \\ \\ { \rm{(x + 1) = {x}^{2} - 3x + 4 }} \\ \\ { \rm{ {x}^{2} - 4x + 3 = 0 }} \\ \\ { \rm{(x - 3)(x - 1) = 0}} \\ \\ { \boxed{ \rm{x_{1} = 3 \: \: and \: \: x _{2} = 1}}} \\ \\ { \boxed{ \tt{remember \: y = x + 1}}} \\ \\ { \rm{y _{1} = 4 \: \: and \: \: y _{2} = 2 }}$

Therefore, points of intersection are two

Answer:  (3, 4) and (1, 2)

Question 2:

Following the steps as in question 1

${ \rm{y = {x}^{2} - 4}} \\ \\{ \rm{2x - 4 = {x}^{2} - 4}} \\ \\ { \rm{ {x}^{2} = 2x }} \\ \\ { \boxed{ \rm{x = 2}}} \\ { \tt{remember : \: y = 2x - 4 }} \\ { \boxed{ \rm{y = 0}}}$

Answer: (2, 0)

7 0

3 years ago

Read 2 more answers

Andre wrote the expression -2 + 4x = 3 to represent the relationship

ankoles [38]

Answer:

4x -2 = 3 and 4x + -2 = 3

Step-by-step explanation:

-2 + 4x = 3 ---- 4x -2 = 3 ------------ 4x + -2 = 3

+2 +2 - 2 +2

------------------ ----------------

4x = 5 4x = 5

---- ---- ----- -----

4 4 4 4

x = 1.25 or 1 1/4 x = 1.25 or 1 1/4

7 0

3 years ago