Question

Assume that females have pulse rates that are normally distributed with a mean of mu equals 73.0 beats per minute and a standard deviation of sigma equals 12.5 beats per minute. Complete parts​ (a) through​ (c) below. a. If 1 adult female is randomly​ selected, find the probability that her pulse rate is between 69 beats per minute and 77 beats per minute. The probability is nothing. ​(Round to four decimal places as​ needed.)

Answer 1

Answer: 0.2510

Step-by-step explanation:

Given : Mean =$\mu=\text{73.0 beats per minute}$

Standard deviation : $\sigma=\text{12.5 beats per minute}$

Sample size : n=1

We assume that females have pulse rates that are normally distributed.

Then , the formula to calculate the z-score is given by :-

$z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}$

For x =69

$z=\dfrac{69-73}{\dfrac{12.5}{\sqrt{1}}}=-0.32$

For x= 77

$z=\dfrac{77-73}{\dfrac{12.5}{\sqrt{1}}}=0.32$

The p-value =$P(-0.32$

$=P(z$

Hence, the  probability that her pulse rate is between 69 beats per minute and 77 beats per minute =0.2510