The first answer is 3/34 sec and the second answer is 15/34 sec.
Set up a proportion for these problems. For the first question,
340/1 = 30/x
Cross multiply:
340*x = 1*30
340x = 30
Divide both sides by 340:
340x/340=30/340
x = 30/340 = 3/34
For the second question,
340/1 = 150/x
Cross multiply:
340*x = 150*1
340x=150
Divide both sides by 340:
340x/340 = 150/340
x = 150/340 = 15/34
Answer:
The answer is below
Step-by-step explanation:
El número de personas que vieron solo A = n (A) = 17
El número de personas que vieron solo B = n (B) = 17
El número de personas que vieron solo C = n (C) = 23
El número de personas que vieron A y B = n (A ∩ B) = 6
El número de personas que vieron A y C = n (A ∩ C) = 8
El número de personas que vieron B y C = n (B ∩ C) = 10
El número de personas que vieron las tres películas = n (A ∩ B ∩ C) = 2
1) Número de estudiantes que han visto dos películas = n (A ∩ B) + n (A ∩ C) + n (B ∩ C) = 6 + 8 + 10 = 24
2)
n (A∩ B '∩ C') = n (A) -n (A ∩ B) -n (A ∩ C) -n (A ∩ B ∩ C) = 17-8-6-2 = 1
n (A'∩ B ∩ C ') = n (B) -n (A ∩ B) -n (B ∩ C) -n (A ∩ B ∩ C) = 17-6-10-2 = 1
n (A'∩ B '∩ C) = norte (C) -n (UNA ∩ C) -n (B ∩ C) -n (UNA ∩ B ∩ C) = 23-8-10-2 = 3
estudiantes que no han visto = 55 - n (A∩ B '∩ C') -n (A'∩ B ∩ C ') - n (A'∩ B ∩ C') - n (A ∩ B) -n ( B ∩ C) -n (UNA ∩ C) -n (A∩ B ∩ C) = 55-1-1-3-6-8-10-2 = 24
3)
número de alumnos que no han visto =
4)
número de estudiantes que vieron solo A = n (A∩ B '∩ C') = 1
Answer:
y = tan(x -π) -1
Step-by-step explanation:
It looks like a straight tangent function shifted down one unit. Since the tangent function has a period of π, ...
tan(x -π) = tan(x)
so you're only looking for the function that has a translation downward of 1 unit. Of course that translation is accomplished by adding -1 to the original function.
The appearance of the graph is of ...
y = tan(x) -1
The choice that is equivalent to this is ...
y = tan(x -π) -1
Answer:
A score of 150.25 is necessary to reach the 75th percentile.
Step-by-step explanation:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
A set of test scores is normally distributed with a mean of 130 and a standard deviation of 30.
This means that 
What score is necessary to reach the 75th percentile?
This is X when Z has a pvalue of 0.75, so X when Z = 0.675.




A score of 150.25 is necessary to reach the 75th percentile.
Answer:
(D) 3, 3, 6
Step-by-step explanation:
The triangle inequality says the sum of the shortest two legs must be longer than the longest. In the case of {3, 3, 6}, the sum is exactly equal to the longest, so the "triangle" will look like a line segment and have zero height and zero area,
Some authors describing the triangle inequality find that to be an acceptable condition. Apparently the author of this question does not.