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horrorfan [7]
3 years ago
5

What is the answer to this problem using correct operations 4-2+8x4+6

Mathematics
1 answer:
exis [7]3 years ago
4 0
Use PEMDAS and solve
4-2+8x4+6
4-2+32+6
now we can solve from left to right
2+32+6
34+6
the answer is 40
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21. The midpoint of UV is (5,-11). The coordinates of one endpoint are U(3,5). Find the coordinates of endpoint V.
natima [27]
I hope this helps you

7 0
3 years ago
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QUESTION 60 What is the mean of the following set of data? Round your answer to two decimal places. {25, 32, 16, 21, 30, 18, 37}
padilas [110]

Question 60:

The answer is B. 25.57.

Mean is calculated by adding up all the values of a data set, and then dividing that sum by the amount of values.

25, 32, 16, 21, 30, 18, 37=179

179÷7=25.57

Question 61:

The answer is A. 102.

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3 0
3 years ago
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I need to know this asap!
Vinvika [58]

w+2x=16 ⇒ w=16-2x


x+2w=14        x+2(16-2x)=14

                      x+32-4x=14

                     -3x=14-32

                      -3x=-18  /:(-3)

                       x=6


w=16-2x=16-2·6=16-12=4


2y+w=-6 ⇒   2y+4=-6

                   2y=-6-4

                   2y=-10  /:2

                   y=-5

4 0
3 years ago
A 15 ounce alloy containing 30% gold was mixed with an alloy containing 5% gold to get an alloy containing 20% gold. How many ou
Studentka2010 [4]

Answer:

4.5 % alloy

Step-by-step explanation:

Let x = amt of 30% alloy

The resulting total is to be 25 oz, therefore:

(25-x) = amt of 5% alloy:

A typical mixture equation:

.30x + .05(25-x) = .20(25)

.30x + 1.25 - .05x = 5 .30x - .05x = 5 - 1.25

.25x = 3.75

x = 3.75%2F.25

x = 15 oz of 30% alloy required

then

25-15 = 10 oz of 5% alloy:

Check solution

.30(15) + .05(10) = .20(25)

4.5 + .5 = 5

4 0
3 years ago
What is the greatest common factor of the terms in the excerpt 21 x -18 x + 28 x y
Mandarinka [93]
X(21-18+28y). axis the greatest common factor
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