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Georgia [21]
3 years ago
9

The water pressure on Mustafa as he dives is increasing at a rate of 0.9920.9920, point, 992 atmospheres (\text{atm})(atm)left p

arenthesis, a, t, m, right parenthesis per meter (\text{m})(m)left parenthesis, m, right parenthesis . What is the rate of increase in water pressure in \dfrac{\text{atm}}{\text{km}} ​km ​ ​atm ​​ start fraction, a, t, m, divided by, k, m, end fraction?
Mathematics
2 answers:
Paha777 [63]3 years ago
8 0
This problem is a simple dimensional analysis. We are simply tasked to express the rate 0.992 atm/m to atm/km.

Dimensional analysis, in simpler terms, is just the process of expressing an answer in another unit by multiplying conversion factors.

For this problem, we'll need to perform the following:

\frac{0.992 atm}{m}= \frac{1000m}{1km} = \frac{992atm}{km}

Notice that we used the conversion factor 1000 meters = 1 kilometer to convert the units from atm/m to atm/km. Thus, we arrive at the final answer 992 atm/km.
RUDIKE [14]3 years ago
8 0

to shorten up the answer it is 992 atm/km

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Step-by-step explanation:

f(x) = 2x² - 6x + 8

you can take a-2 and substitute it for each x, which would look like this:

f(a-2) = 2(a-2)² - 6(a-2) + 8

then distribute those in ( )

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Approximately how many liters are in 20 gallons 1 L 0.26 gal.
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Answer:

77 litres

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1L = 0.26 gal

0.26 gal = 1L

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What is the simplified form of the following expression? Assume y=0 ^3 sqrt 12x^2/16y
pochemuha

For this case we must simplify the following expression:

\sqrt [3] {\frac {12x ^ 2} {16y}}

We rewrite the expression as:

\sqrt[3]{\frac{4(3x^2)}{4(4y)}}=\\\sqrt[3]{\frac{4(3x^2)}{4(4y)}}=\\\frac{\sqrt[3]{3x^2}}{\sqrt[3]{4y}}=

We multiply the numerator and denominator by:

(\sqrt[3]{4y})^2:\\\frac{\sqrt[3]{3x^2}*(\sqrt[3]{4y})^2}{\sqrt[3]{4y}*(\sqrt[3]{4y})^2}=

We use the rule of powera ^ n * a ^ m = a ^ {n + m} in the denominator:

\frac{\sqrt[3]{3x^2}*(\sqrt[3]{4y})^2}{(\sqrt[3]{4y})^3}=\\\frac{\sqrt[3]{3x^2}*(\sqrt[3]{4y})^2}{4y}=

Move the exponent within the radical:

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Answer:

\frac{\sqrt[3]{6x^2*y^2}}{2y}

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