Answer:
The area of the shaded region is 42.50 cm².
Step-by-step explanation:
Consider the figure below.
The radius of the circle is, <em>r</em> = 5 cm.
The sides of the rectangle are:
<em>l</em> = 11 cm
<em>b</em> = 11 cm.
Compute the area of the shaded region as follows:
Area of the shaded region = Area of rectangle - Area of circle
![=[l\times b]-[\pi r^{2}]\\\\=[11\times 11]-[3.14\times 5\times 5]\\\\=121-78.50\\\\=42.50](https://tex.z-dn.net/?f=%3D%5Bl%5Ctimes%20b%5D-%5B%5Cpi%20r%5E%7B2%7D%5D%5C%5C%5C%5C%3D%5B11%5Ctimes%2011%5D-%5B3.14%5Ctimes%205%5Ctimes%205%5D%5C%5C%5C%5C%3D121-78.50%5C%5C%5C%5C%3D42.50)
Thus, the area of the shaded region is 42.50 cm².
8/36
Divide the numerator and the denominator by 4
2/9
That's the simplest form
Have an awesome day! :)
Answer:
the chances of you gettin a odd number is 3/6 since you have 1 3 and 5
Step-by-step explanation:
Answer:
Step-by-step explanation:
The arcs LY, KM, KL and MJ together form the full revolution angle, thus
Note that
then
So,
Also
so
In triangle EML,
Thus,
The second graph is correct.
There will be a vertical asymptote at x=0, since we cannot divide by 0. Using the x-axis on the second graph, if we substitute 5 in for x, we have 100/5+20 = 20+20=40. There is a point on this graph here. Using 10 for x, we have 100/10+20 = 10+20 = 30. There is a point on the graph here. Every point matches.
