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3 years ago

Please help 99 points!!!! 6x-3=3x-9

Mathematics

2 answers:

german3 years ago

7 0

I think It would be x= -1

kari74 [83]3 years ago

5 0

<u><em>Answer: x=-2</em></u>

Step-by-step explanation:

addition property of equality is adding the same number to both sides of an equation does not change the equation.

distributive property: a(b+c)=ab+ac

add 3 both sides of an equation.

6x-3+3=3x-9+3

simplify an equation

6x=3x-6

subtract 3x both sides of an equation

6x-3x=3x-6-3x

simplify

3x=-6

divide 3 both sides of an equation

3x/3=-6/3

simplify

-6/3=-2

the answer should be the negative sign.

x=-2

Hope this helps!

Thanks!

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Which of the following represents the set of possible rational roots for the

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Answer: plus or minus 1, 1/2, 2, 5, 5/2, and 10

Explanation:

To find the possible roots

We first find the factor of the constant term:

10: 1, 2, 5, 10

Then we find the factor of leading coefficient:

2: 1, 2

And the possible rational roots are:

Plus or minus [1/1, 1/2, 2/1, 2/2, 5/1, 5/2, 10/1, 10/2]

Then we get rid of the duplicate:

Plus or minus [1, 1/2, 2, 5, 5/2, 10]

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3 years ago

A simple random sample of size nequals81 is obtained from a population with mu equals 83 and sigma equals 27. (a) Describe the

Ivanshal [37]

Answer:

a) $\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

b) $z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

c) $z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

d) $z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

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Step-by-step explanation:

For this case we know the following propoertis for the random variable X

$\mu = 83, \sigma = 27$

We select a sample size of n = 81

Part a

Since the sample size is large enough we can use the central limit distribution and the distribution for the sampel mean on this case would be:

$\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

Part b

We want this probability:

$P(\bar X>89)$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 89 we got:

$z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

Part c

$P(\bar X$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 75.65 we got:

$z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

Part d

We want this probability:

$P(79.4 < \bar X < 89.3)$

We find the z scores:

$z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

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