If a< c< b then a<c and c<b
Separate the equation into 2 separate ones and solve them:
X-9 < 4x +3
Subtract 3 from both sides:
X-12 < 4x
Subtract x from both sides:
-12< 3x
Divide both sides by 3:
X > -4
4x+3 < 27
Subtract 3 from both sides
4x < 24
Divide both sides by 4
X <6
Combine to get one inequality:
-4<x<6
Answer:
x = 18.5
Step-by-step explanation:
Given
+
= 10
Multiply through by 4 to clear the fractions
2x + 3 = 40 ( subtract 3 from both sides )
2x = 37 ( divide both sides by 2 )
x =
= 18.5
Answer:
5x + 6y = 20_____(1)
8x - 6y = -46_____(2)
Solving simultaneously:
Eqn(1) + Eqn(2)
5x + 8x + 6y + (-6y) = 20 + (-46)
13x = -26
x = -2
substituting this into Eqn (1):
5(-2) + 6y = 20
-10 + 6y = 20
6y = 30
y = 5
hence:
x = -2,y = 5.