Answer:
The equation of line with slope -7 passing through (5,9) in point-slope form is:
Step-by-step explanation:
Given
Slope of line = m = -7
Point = (5,9)
The point slope form of equation is obtained from a point and slope. It is given by the equation:
We know that (x1,y1) = (5,9)
Putting the values we get
Hence,
The equation of line with slope -7 passing through (5,9) in point-slope form is:
Answer:
for the first one
77 for the second one
the last one is -72x^-5
Step-by-step explanation:
i dont know about the other two, but i hope these answers help
The answer is x^2 - 4x +4. What I did was set it up as a ratio, FOILing out the two denominators on the left to get (x-5)?/(x^2 - 7x + 10) = (x+1)/1. Next I cross-multiplied to get (x-5)? = (x+1)(x^2 - 7x + 10). Next I FOILed out the right side to get (x-5)? = x^3 - 9x^2 + 24x - 20. Now I have an equation just like 3x=9, for example, where I divide both sides by 3 to find x. Instead, since we have polynomials, we have to use long division. Divide the x^3 term by x-5 and you'll get it.
Do 7.50 times 4 and you get 30 so it’s 30
ok so original perimeter = 12 +12 + 17 +17 = 58 mm
if dimensions are multiplied by 12:
12*12 = 144 and 17*12 = 204
new perimeter = 144 +144 +204 +204 = 696 mm
696 / 58 = 12
so the perimeter increased by a factor of 12, answer is A