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3 years ago

10

I don’t get solving equations with variables on both sides word problems. Can someone please help explain it to me because my te

acher doesn’t really explain very good

1 answer:

salantis [7]3 years ago

8 0

The object of any equation with a variable (whether it is on one side or both) is to isolate the variable. We do this by moving all of the x's to one side of the equation and everything else to the other side.

For example:

3x - 5 = 2x + 1

<u>-2x </u> <u>-2x </u>

x - 5 = 1

<u> +5 </u> <u> +5 </u>

x = 6

Now, there are 3 different types of solutions:

1) x = ____ there is one solution

2) 0 = 0 <em>or some other TRUE statement </em>there are infinite solutions <em>because every value for x is a solution</em>

3) 0 = 1 <em>or some other FALSE statement </em>there are no solutions <em>because no value for x will provide a solution</em>

HOPE THIS HELPED!

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What is the sign of f on the interval -2

TEA [102]

Answer:

$f$ is sometimes positive and sometimes negative.

Step-by-step explanation:

$f(x)=(x-3)(x+2)(x+4)(x+4)(x-1)(2x-9)$

Take $x=-1\in(-2,\frac{9}{2})\ as-2$

$f(-1)=(-1-3)(-1+2)(-1+4)(-1-1)(-2-9)\\\\=(-4)(1)(3)(-2)(-11)\\\\=-264\\\\f(-1)$

Take $x=2\in(-2,\frac{9}{2})\ as\ -2$

$f(2)=(2,-3)(2+2)(2+4)(2-1)(2\times2-9)\\\\=(-1)(4)(6)(1)(-5)\\\\=120\\\\f(2)>0$

Hence $f(x)$ for $x=-1$ and $f(x)>0$ for $x=2$

So $f$ is sometimes positive and sometimes negative in the interval.

3 0

3 years ago

(2x - 1) ft<br> (x + 4) ft<br> 7 ft

anygoal [31]

What is the question?

7 0

3 years ago

X+3/2 + (x-1) = 4/5

tester [92]

Answer:

x = $\frac{3}{20}$

Step-by-step explanation:

Given

x + $\frac{3}{2}$ + (x - 1) = $\frac{4}{5}$

Multiply through by 10 ( the LCM of 2 and 5 ) to clear the fractions

10x + 15 + 10(x - 1) = 8

10x + 15 + 10x - 10 = 8

20x + 5 = 8 ( subtract 5 from both sides )

20x = 3 ( divide both sides by 20 )

x = $\frac{3}{20}$

3 0

3 years ago

Read 2 more answers

Find the equation for the plane that contains the line x=−1+3t , y=1+2t, z=2+4t and is perpendicular to the plane containing the

Ivan

Let $L$ be the line given by the vector equation

$(-1,1,2) + \lambda(3,2,4) \ , \lambda \in \mathbb{R}$ .

First, we use the director vectors of the lines L1 and L2 to get the

vector equation of the plane containing them, which we denote by $\Pi_1$ . This is,

$\\\\\Pi_1 : (1,-1,5) + \alpha (2,-1,6) + \beta (1,1,-3) \ , \alpha, \beta \in \mathbb{R}\\\\\\$

We observe that $\vec{N} = (2,-1,6)\times(1,1,-3) = (-3,12,3) \ne (0,0,0)$ . Therefore, the vector equation of $\Pi_1$ defines a plane and $\vec{N}$ is a normal vector to $\Pi_1.$

Finally, the vector equation for the wanted plane, which we denote by $\Pi$ , is

$\Pi : (-1,1,2) + r(3,2,4) + s(-3,12,3), r,s \in \mathbb{R} \ .$

Thus, if $s = 0$ , then $L \subset \Pi$ and since $\vec{N}$ is parallel to $\Pi$ , then it is perpendicular to $\Pi_1$ .

8 0

3 years ago

How do you work out the equation 1-x=9.

mafiozo [28]

Answer:

x=8

Step-by-step explanation:

x + 1 = 9

Simplifying

x + 1 = 9

Reorder the terms:

1 + x = 9

Solving

1 + x = 9

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-1' to each side of the equation.

1 + -1 + x = 9 + -1

Combine like terms: 1 + -1 = 0

0 + x = 9 + -1

x = 9 + -1

Combine like terms: 9 + -1 = 8

x = 8

Simplifying

x = 8

7 0

4 years ago