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yulyashka [42]
2 years ago
6

In which graph is y a direct variation of x? A. B. C. D.

Mathematics
1 answer:
TEA [102]2 years ago
8 0

Answer:

D

Step-by-step explanation:

The line is going through the origin.

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If you had 1052 toothpicks and were asked to group them in powers of 6, how many groups of each power of 6 would you have? Put t
sukhopar [10]

1052 toothpicks can be grouped into 4 groups of third power of 6 (6^{3}), 5 groups of second power of 6 (6^{2}), 1 group of first power of 6 (6^{1}) and 2 groups of zeroth power of 6 (6^{0}).

The number 1052, written as a base 6 number is 4512

Given: 1052 toothpicks

To do: The objective is to group the toothpicks in powers of 6 and to write the number 1052 as a base 6 number

First we note that, 6^{0}=1,6^{1}=6,6^{2}=36,6^{3}=216,6^{4}=1296

This implies that 6^{4} exceeds 1052 and thus the highest power of 6 that the toothpicks can be grouped into is 3.

Now, 6^{3}=216 and 216\times 5=1080, 216\times 4=864. This implies that 216\times 5 exceeds 1052 and thus there can be at most 4 groups of 6^{3}.

Then,

1052-4\times6^{3}

1052-4\times216

1052-864

188

So, after grouping the toothpicks into 4 groups of third power of 6, there are 188 toothpicks remaining.

Now, 6^{2}=36 and 36\times 5=180, 36\times 6=216. This implies that 36\times 6 exceeds 188 and thus there can be at most 5 groups of 6^{2}.

Then,

188-5\times6^{2}

188-5\times36

188-180

8

So, after grouping the remaining toothpicks into 5 groups of second power of 6, there are 8 toothpicks remaining.

Now, 6^{1}=6 and 6\times 1=6, 6\times 2=12. This implies that 6\times 2 exceeds 8 and thus there can be at most 1 group of 6^{1}.

Then,

8-1\times6^{1}

8-1\times6

8-6

2

So, after grouping the remaining toothpicks into 1 group of first power of 6, there are 2 toothpicks remaining.

Now, 6^{0}=1 and 1\times 2=2. This implies that the remaining toothpicks can be exactly grouped into 2 groups of zeroth power of 6.

This concludes the grouping.

Thus, it was obtained that 1052 toothpicks can be grouped into 4 groups of third power of 6 (6^{3}), 5 groups of second power of 6 (6^{2}), 1 group of first power of 6 (6^{1}) and 2 groups of zeroth power of 6 (6^{0}).

Then,

1052=4\times6^{3}+5\times6^{2}+1\times6^{1}+2\times6^{0}

So, the number 1052, written as a base 6 number is 4512.

Learn more about change of base of numbers here:

brainly.com/question/14291917

6 0
2 years ago
The sum of three consecutive multiples"<br>of 8 is 192. Find the multiples.​
goblinko [34]

Answer:

7,8,9

Step-by-step explanation:

192/8=24

X+(x+1)+(x+2)=24

3x+3=24

3x=21

x=7

so it’s 7,8,9

8 0
2 years ago
Read 2 more answers
What is the length of the unknown leg of the right​ triangle? And please put the answer as a decimal
irga5000 [103]

Answer:

3.87 ft = Length of unknown side of the right triangle.

Step-by-step explanation:

Given,

Hypotenuse = 4 ft

Base = 1 ft

Altitude = x

Hypotenuse² = Base² + Altitude²

4² = 1² + x²

4² - 1² = x²

16 - 1 = x²

15 = x²

√15 ft = x

3.87 ft = x

Hope it helps ⚜

6 0
1 year ago
Read 2 more answers
Find the volume of the cylinder.
KiRa [710]

Answer:

  12π ≈ 37.7 cubic centimeters

Step-by-step explanation:

The volume of the cylinder can be found using the appropriate formula.

__

<h3>dimensions</h3>

The cylinder is marked as having a diameter of 4 cm, and a height of 3 cm. The radius of the cylinder is half the diameter:

  r = d/2

  r = (4 cm)/2 = 2 cm

__

<h3>formula for volume</h3>

The formula for the volume of a cylinder is ...

  V = πr²h . . . . . . where r is the radius and h is the height

Using the dimensions given, we find the volume to be ...

  V = π(2 cm)²(3 cm) = π(4 cm²)(3 cm) = 12π cm³

Written as a decimal, the volume is about ...

  12π cm³ ≈ 37.70 cm³ . . . . volume of the cylinder

_____

<em>Additional comment</em>

You probably noticed that we used the units in the formula along with the numbers. Units abbreviations can be manipulated algebraically the same way any other variable can be:

  x · x = x²

  cm · cm = cm²

Computing the volume in more steps, we have ...

  V = π(2 cm)²(3 cm)

  = π(2 cm)(2 cm)(3 cm) . . . . expanding the square term

  = π(2)(2)(3)(cm)(cm)(cm) . . . . we can rearrange the factors of a product

  = π(12)(cm³)

  = 12π cm³

7 0
2 years ago
Read 2 more answers
Create an equivalent expression for 11−7 • 115.
iogann1982 [59]

The equivalent expression to 11^-7 × 11^5 is one over eleven raised to the second power. option A

Exponential

11^-7 × 11^5

= 11^(-7+5)

= 11^(-2)

= 1 / 11²

Options:

one over eleven raised to the second power

(1/11)²

one over eleven raised to the power of negative two

(1/11)^-2

11^2

−11^2

Therefore, the equivalent expression to 11^-7 × 11^5 is one over eleven raised to the second power.

Learn more about exponential:

brainly.com/question/27161222

#SPJ1

4 0
1 year ago
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