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Alla [95]
3 years ago
11

Which of the following terms best describes a comparison of two numbers?

Mathematics
2 answers:
Yakvenalex [24]3 years ago
6 0

Answer:

a ratio is a comparison between two numbers.

Step-by-step explanation:

mark me brainliest if this helps :)

Ivenika [448]3 years ago
3 0

Answer: ratio

Step-by-step explanation:

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How to factor 3n+5n+2
AlladinOne [14]

Answer:

8n+2

Step-by-step explanation:

You add 3n to 5n and that gets you 8n.

The 2 is just alone.

5 0
3 years ago
Read 2 more answers
X - 6 = 5x – 2<br> help
KiRa [710]

Answer:

-6+2=5x-x

-4=4x

-4/4=X

0=x

8 0
2 years ago
Find the midpoint of points A(8,-7) and B(3,-1) graphically
sukhopar [10]

Answer: (5.5, -4)

Step-by-step explanation:

You can use the midpoint formula to find the midpoint of point A and point B.

M(\frac{x_{1}+x_{2} }{2}, \frac{y_{1} + y_{2} }{2})

x₁ = 8

x₂ = 3

y₁ = -7

y₂ = -1

M(\frac{x_{1}+x_{2} }{2}, \frac{y_{1} + y_{2} }{2})

M(\frac{8+3 }{2},  \frac{-7 +-1}{2} )

M(\frac{8+3 }{2},  \frac{-7 -1}{2} )

M(\frac{11 }{2},  \frac{-8}{2} )

M(5.5, -4 )

Midpoint = (5.5, -4)

Hope this helps!

3 0
2 years ago
A certain species of fish require 1.5 cubic feet of water per fish to maintain a healthy
sertanlavr [38]
7 of them fish I’m not going to lye I just wanted to put 7 but I have to have at least 20 characters
6 0
3 years ago
A researcher is going to estimate the average typing speed of students of a college. He selects a random sample of 20 students a
Stella [2.4K]

Answer:

The margin of error of the 90% confidence interval of a student's average typing speed is of 1.933 wpm.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 20 - 1 = 19

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 19 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.9}{2} = 0.95. So we have T = 1.7291

The margin of error is:

M = T\frac{s}{\sqrt{n}}

In which s is the standard deviation of the sample and n is the size of the sample. For this question, we have s = 5, n = 20. So

M = T\frac{s}{\sqrt{n}}

M = 1.7291\frac{5}{\sqrt{20}}

M = 1.933

The margin of error of the 90% confidence interval of a student's average typing speed is of 1.933 wpm.

8 0
3 years ago
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