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2 years ago

Suppose a car has a rating of 4.8 gallons per 100 miles. What is the miles-per-gallon rating of this car?

Mathematics

1 answer:

bezimeni [28]2 years ago

4 0

Answer:

The miles-per-gallon rating of this car is 20.83.

Step-by-step explanation:

This question can be solved by a rule of three.

What is the miles-per-gallon rating of this car?

How many miles for 1 gallon?

4.8 gallons are used for 100 miles. So

4.8 gallons - 100 miles

1 gallon - x miles

$4.8x = 100$

$x = \frac{100}{4.8}$

$x = 20.83$

The miles-per-gallon rating of this car is 20.83.

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Robin baked 702 cookies.He sold them in boxes of 18. After selling all of the boxes of cookies for the same amount each, he earn

loris [4]

Answer:

cost of a box is $3.5

Step-by-step explanation:

given data

sold box = 18

earned = $136.50

solution

we consider here number of boxes of cookies is x

and

for we get Tyler sold cookies box so number of boxes we divide 702 cookies among 18 is

Tyler sold = $\frac{702}{18}$

Tyler sold = 39 boxes

and

now we consider here y as cost of each box of cookies,

so for cost or sale price of the cookie boxes here we divided 136.50 dollars among 39 boxes

cost of each box = $\frac{136.5}{39}$

cost of each box = 3.5

Thus, the cost of each box was 3.5

3 0

3 years ago

jordan is cutting a 2 m by 1 1/4 m piece of rectangular paper into two pieces along its diagonal. find the area of each of the p

alexdok [17]

Answer:

The area of a rectangle is 5/4

Step-by-step explanation:

5 0

2 years ago

Write an equation of the line that passes through the points (0,4)(0,4) and (2,10)(2,10). $y=

lutik1710 [3]

I am going to guess you want to find a line which passes through the points (0,4) and (2,10)...

y₂-y₁ / x₂-x₁
10 - 4 / 2 - 0
6 / 2
3....slope
(0,4) .....b

y = 3x + 4

3 0

3 years ago

True or False?

neonofarm [45]

$FALSE!\\The\ segments\ below\ couldn't\ form\ a\ triangle.\\\\a,b,c-lengths\ sides\ of\ a\ triangle,\ then:\\\\a+b > c\\a+c > b\\b+c > c\\\\Here:a=9;\ b=4;\ c=15\\\\a+b=9+4=13 < 15!!!!$

7 0

2 years ago

The following data gives the speeds (in mph), as measured by radar, of 10 cars traveling north on I-15. 76 72 80 68 76 74 71 78

____ [38]

Answer:

71.123 mph ≤ μ ≤ 77.277 mph

Step-by-step explanation:

Taking into account that the speed of all cars traveling on this highway have a normal distribution and we can only know the mean and the standard deviation of the sample, the confidence interval for the mean is calculated as:

$m-t_{a/2,n-1}\frac{s}{\sqrt{n} }$ ≤ μ ≤ $m+t_{a/2,n-1}\frac{s}{\sqrt{n} }$

Where m is the mean of the sample, s is the standard deviation of the sample, n is the size of the sample, μ is the mean speed of all cars, and $t_{a/2,n-1}$ is the number for t-student distribution where a/2 is the amount of area in one tail and n-1 are the degrees of freedom.

the mean and the standard deviation of the sample are equal to 74.2 and 5.3083 respectively, the size of the sample is 10, the distribution t- student has 9 degrees of freedom and the value of a is 10%.

So, if we replace m by 74.2, s by 5.3083, n by 10 and $t_{0.05,9}$ by 1.8331, we get that the 90% confidence interval for the mean speed is:

$74.2-(1.8331)\frac{5.3083}{\sqrt{10} }$ ≤ μ ≤ $74.2+(1.8331)\frac{5.3083}{\sqrt{10} }$

74.2 - 3.077 ≤ μ ≤ 74.2 + 3.077

71.123 ≤ μ ≤ 77.277

8 0

2 years ago