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3 years ago

3x-6y=6 in function notation

1 answer:

3 0

Subtract 3x from both sides:

-6y = -3x + 6

divide both sides by -6 to get y by itself:

y = 1/2x - 1

function notation is rewriting y as a function:

f(x) = 1/2x -1

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1.) p^2+14p-38=0<br> what the vertex?

Lelu [443]

Answer:

vertex = (- 7, - 87)

Step-by-step explanation:

given a parabola in standard form : ax² + bx + c : a ≠ 0

Then the x- coordinate of the vertex is

$x_{vertex}$ = - $\frac{b}{2a}$

p² + 14p - 38 is in standard form

with a = 1, b = 14, c = - 38, hence

$x_{vertex }$ = - $\frac{14}{2}$ = -7

substitute x = - 7 into the equation for corresponding value of y

y = (- 7)² + 14(- 7) - 38 = 49 - 98 - 38 - - 87

vertex = (- 7, - 87)

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3 years ago

What are the roots of the polynomial equation x2 + x- 72 =0

Alex17521 [72]

First, you can factor them into (x-8)(x+9)=0 then set x-8=0 and x+9=0, in which you get X = 8 or X = -9

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3 years ago

Which number has the least absolute value? A) −5 B) −10 C) −20 D) −30

blsea [12.9K]

The correct answer is D because -30 is far away from 0

8 0

3 years ago

Read 2 more answers

4+x/ 4-x<br> Using quotient rule differentiate with respect to x

oee [108]

Hope this helps! Let me know if it doesn’t make sense

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3 years ago

The average density of the material in intergalactic space is approximately 2.5 × 10–27 kg/m3. what is the volume of a lead samp

Lesechka [4]

Answer:

e. $1.8\times 10^{-6}m^3$

Step-by-step explanation:

It is given that,

The density of intergalactic space material is $2.5 \times 10^{-27}$ kg per cubic meter.

And the volume of intergalactic space material is $8.0\times 10^{24} m^3$

So the mass of that much intergalactic space material is,

$m= \rho\times v$ , where 'm' is the mass, and 'v' is the volume.

Putting the values we get,

$m=2.5 \times 10^{-27}\times 8.0 \times 10^{24}$

$m=20\times 10^{(-27+24)}=20\times 10^{-3} kg$

It is also given that the mass of lead is the same as the mass of the intergalactic space material. Therefore, the mass of lead is $20 \times 10^{-3}=2 \times 10^{-2}kg$

So the volume of lead is,

$v=\frac{m}{\rho} =\frac{2 \times 10^{-2}}{11300} = 0.00000177 m^3$

$v=1.77 \times 10^{-6}=1.8\times 10^{-6}m^3$

So the volume of lead is $v=1.8\times 10^{-6}m^3$ .

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3 years ago