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harkovskaia [24]
3 years ago
8

What value in place of the question mark makes the polynomial below a perfect square trinomial? 9x2+?x+64

Mathematics
2 answers:
Artist 52 [7]3 years ago
7 0

Answer:

When A = 48, the polynomial  9x^2+Ax+64 a perfect square trinomial.

Step-by-step explanation:

 Given : the polynomial 9x^2+Ax+64

We have to find the value of A that makes the polynomial a perfect square trinomial.

For a trinomial to be a perfect square trinomial when it can be written in form of a perfect square as (a+b)^2=a^2+b^2+2ab

Consider the given polynomial 9x^2+Ax+64

Comparing the given polynomial with the right side of the above identity,

9x^2+Ax+64 can be written as (3x)^2+Ax+(8)^2

We have,

a = 3x , b = 8

also , 2ab = Ax

2(3x)(8) = Ax

⇒ 48 = A

Thus, When A = 48, the polynomial  9x^2+Ax+64 a perfect square trinomial.

serg [7]3 years ago
4 0
9x² + bx + 64
\/(9x²) = 3x
\/84 = 8
2*3x*8 = 48x
b = 48
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