Answer:
No Real Solution: 12x-4=6(2x-4)
One Real Solution: 3x+8-x=4x+8
Infinitely Many Solutions: 4(x+1)=4-4x
Step-by-step explanation:
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Answer:
You can make 64 different sums (which includes a sum of $0 using none of the coins).
Step-by-step explanation:
The number of sums you can make is equal to:
⁶C₀ + ⁶C₁ + ⁶C₂ + ⁶C₃ + ⁶C₄ + ⁶C₅ +⁶C₆ = 1 + 6 + 15 + 20 + 15 + 6 + 1 = 64
Answer:
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Step-by-step explanation:
Given that;
n=6 , m=2 , z1 is the average of the elements of x , and z2 is the average of the first three elements of x minus the average of fourth through sixth elements of x
So, Let d=n∧28, d′=n∧22.
We have nd=10, nd′=20n
so
n=10d=20d′nwhenced=2d′.
On the other hand, d is a divisor of 28, and above shows d′ is, too. As it is also a divisor of 22, the only possibilities are d′=1, d′=2, corresponding to d=2, d=4.
However, if d=2, n=20, and 20∧28=4, not 2. So the only solution is d=4, and n=40.
Answer:
Step-by-step explanation:
