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omeli [17]
2 years ago
5

What is 2 and 3/4 divided by 1/4

Mathematics
1 answer:
Tanya [424]2 years ago
3 0
2 3/4 divided by 1/4
is
2 3/4 multiplied by 4/1

which is (2+3/4)*4 = 2*4 + 3/4*4 = 8+3 =<em>11</em>
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If -3x-8=16 what is the value of -2(x-7)
777dan777 [17]

Answer:

-3x-8=16

-3x = 16+8

-3x = 24

x = 24/-3

x = -8

= -2(x-7)

= -2(-8-7)

= 30

Hope this helps you. Do mark me as brainliest.

4 0
2 years ago
Ralph and Jody go to the store to buy chips and candy bars. Ralph buys 3 bags of potato chips and 4 candy bars for 375 cents. Jo
s2008m [1.1K]
3x+4y = 375
6x+ 4y= 600
-------------------
6x-3x  = 600 - 375

3x=225
x=225:3
x=75 cents

3*x+4y= 375
3*75+4y=375
225 +4y = 375
4y=375-225
4y=150
y=150:4
y=37,5 cents

the price is 75+37,5=112,5 cents for one bag of potato chips and one candy bar

3 0
3 years ago
A function follows the rule y = -75 - 5 x . When the function's output is 25, the equation is 25 = -75 - 5 x .
zhenek [66]

Answer:

same here idek tbh

Step-by-step explanation:

.......

3 0
2 years ago
If a coin is tossed three times, find probability of getting
Assoli18 [71]

{\large{\textsf{\textbf{\underline{\underline{Given :}}}}}}

‣ A coin is tossed three times.

{\large{\textsf{\textbf{\underline{\underline{To \: Find :}}}}}}

‣ The probability of getting,

1) Exactly 3 tails

2) At most 2 heads

3) At least 2 tails

4) Exactly 2 heads

5) Exactly 3 heads

{\large{\textsf{\textbf{\underline{\underline{Using \: Formula :}}}}}}

\star \: \tt  P(E)= {\underline{\boxed{\sf{\red{  \dfrac{ Favourable \:  outcomes }{Total \:  outcomes}  }}}}}

{\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}

★ When three coins are tossed,

then the sample space = {HHH, HHT, THH, TTH, HTH, HTT, THT, TTT}

[here H denotes head and T denotes tail]

⇒Total number of outcomes \tt [ \: n(s) \: ] = 8

<u>1) Exactly 3 tails </u>

Here

• Favourable outcomes = {HHH} = 1

• Total outcomes = 8

\therefore  \sf Probability_{(exactly  \: 3 \:  tails)}  =  \red{ \dfrac{1}{8}}

<u>2) At most 2 heads</u>

[It means there can be two or one or no heads]

Here

• Favourable outcomes = {HHT, THH, HTH, TTH, HTT, THT, TTT} = 7

• Total outcomes = 8

\therefore  \sf Probability_{(at \: most  \: 2 \:  heads)}  =  \green{ \dfrac{7}{8}}

<u>3) At least 2 tails </u>

[It means there can be two or more tails]

Here

• Favourable outcomes = {TTH, TTT, HTT, THT} = 4

• Total outcomes = 8

\longrightarrow   \sf Probability_{(at \: least \: 2 \:  tails)}  =  \dfrac{4}{8}

\therefore  \sf Probability_{(at \: least \: 2 \:  tails)}  =   \orange{\dfrac{1}{2}}

<u>4) Exactly 2 heads </u>

Here

• Favourable outcomes = {HTH, THH, HHT } = 3

• Total outcomes = 8

\therefore  \sf Probability_{(exactly \: 2 \:  heads)}  =  \pink{ \dfrac{3}{8}}

<u>5) Exactly 3 heads</u>

Here

• Favourable outcomes = {HHH} = 1

• Total outcomes = 8

\therefore  \sf Probability_{(exactly \: 3 \:  heads)}  =  \purple{ \dfrac{1}{8}}

\rule{280pt}{2pt}

8 0
1 year ago
Jamie and his two brothers divided a package of 125 toy cars equally. About how many cars did each of them receive
sp2606 [1]

41 and there are two left

8 0
3 years ago
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