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3 years ago

You are giving 5 cards out of 52 you return 2 what is the probability that you returned 2 aces back to the dealer

Mathematics

1 answer:

ohaa [14]3 years ago

3 0

2/52 chances or 1/26

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PLEASE HELP!!! WORTH 3 GRADES

Rufina [12.5K]

The correct answer should be D

6 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%5Cbegin%7Bequation%7D%5Ctext%20%7B%20Question%3A%20Find%20the%20value%20of%20%7D%20%5Cfrac%7B

ankoles [38]

$\bold{Heya!}$

Your answer to this is:

$\sf{= \frac{1}{2} \: + \frac{2}{1 \: + \: x^2} \: + \: \frac{1}{1 \: + \: x^4} \: + \: \frac{2^1^0^0}{1 \: + \: x^2^0^0}$

<h2>→ <u>EXPLANATION :-</u></h2>

<u />

<u /> $\sf{= \frac{1}{2} \: + \frac{2}{1 \: + \: x^2} \: + \: \frac{1}{1 \: + \: x^4} \: + \: \frac{2^1^0^0}{1 \: + \: x^2^0^0} \: (1)$

$\sf{Apply \: rule:} \: (a) = a$

$\sf{(1) = 1$

$\sf{= \frac{1}{2} \: + \frac{2}{1 \: + \: x^2} \: + \: \frac{1}{1 \: + \: x^4} \: + \: \frac{2^1^0^0}{1 \: + \: x^2^0^0} \: ^. \: 1$

$\sf{\frac{1}{1 \: + \:1} = \frac{1}{2}$

$\sf{\frac{2^1^0^0}{1 \: + \: x^2^0^0} ^.^ \: 1 \: = \: \frac{2^1^0^0}{1 \: + \: x^2^0^0}$

$\sf{= \frac{1}{2} \: + \frac{2}{1 \: + \: x^2} \: + \: \frac{1}{1 \: + \: x^4} \: + \: \frac{2^1^0^0}{1 \: + \: x^2^0^0}$

Hopefully This Helps ! ~

#LearnWithBrainly

$\underline{Answer :}$

<em>Jaceysan ~</em>

7 0

2 years ago

The measure of angle D is 5 times the measure of angle E. The two angles are supplementary. Find the measure of each angle

steposvetlana [31]

Angle e = x angle d = 5x supplementary means they add up to 180
x + 5x =180
6x = 180
6x/6 = 180/6
x = 30
so angle e = 30 and angle d = 5(30) = 150

4 0

4 years ago

Match the graph to the related table.

lana66690 [7]

Answer:

Option C

Step-by-step explanation:

Option c is right answer

3 0

3 years ago

Read 2 more answers

In this truss bridge, AAOB ABDC. AO=5 meters, BD=10 meters, AB=5 meters. What is the length of BC? A. 5 m B. 8 m C. 10 m D. 15 m

Olenka [21]

Consider $\Delta AOB\cong \Delta BDC$ .

Given:

$\Delta AOB\cong \Delta BDC, AO=5\ m,BD=10\ m, AB=5\ m.$

To find:

The length of BC.

Solution:

We have,

$\Delta AOB\cong \Delta BDC$

We know that the corresponding parts of congruent triangles are congruent (CPCTC).

$AB=BC$ (CPCTC)

$5\ m=BC$

The length of BC is 5 m. Therefore, the correct option is A.

5 0

3 years ago