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myrzilka [38]
3 years ago
14

Find a power series representation of e^x sin(x)

Mathematics
1 answer:
liberstina [14]3 years ago
6 0
The Taylor series is defined by:
f(x) = \sum \frac{f^n (a)}{n!} (x-a)^n

Let a = 0.
Then its just a matter of finding derivatives and determining how many terms is needed for the series.

Derivatives can be found using product rule:
f^n (x) = e^x g^{n-1} (x) + e^x g^n (x)  \\ g^0 (x) = sin x

Do this successively to n = 6.
f^1 (x) = e^x (sinx +cos x) \\ f^2 (x) = e^x (2cos x)  \\ f^3 (x) = e^x(2cos x - 2sin x)  \\ f^4 (x) = e^x (-4 sin x)  \\ f^5 (x) = e^x(-4sinx -4cos x) \\ f^6(x) = e^x(-8cos x)

Plug in x=0 and sub into taylor series:
e^x  sin x = x+x^2 +\frac{x^3}{3} -\frac{x^5}{30}-\frac{x^6}{90}...

If more terms are needed simply continue the recursive derivative formula and add to taylor series.
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Which line has a constant of proportionality between y and x of 1/2?
Gnesinka [82]

Answer:

It's line C.

Step-by-step explanation:

the slope of line C is 1/2 so that's the constant of proportionality

6 0
2 years ago
Explain why each non-zero integer has two square roots but only one cube root.
lilavasa [31]

if we have a number like say hmm 4, and we say hmmm √4 is ±2, it simply means, that if we multiply that number twice by itself, we get what's inside the root, we get the 4, so (+2)(+2) = 4, and (-2)(-2) = 4, recall that <u>minus times minus = plus</u>.

so, any when we're referring to even roots like \bf \sqrt[2]{~~},\sqrt[4]{~~},\sqrt[6]{~~}...., the positive number, that can multiply itself an even amount of times, will produce a valid value, BUT the negative number that multiply itself an even amount of times, will also produce a valid value.

now, that's is not true for odd roots like \bf \sqrt[3]{~~},\sqrt[5]{~~},\sqrt[7]{~~}...., because the multiplication of the negative number will not produce a valid value, let's put two examples on that.


\bf \sqrt[3]{27}\implies \sqrt[3]{3^3}\implies 3\qquad because\qquad (3)(3)(3)=27&#10;\\\\\\&#10;however\qquad (-3)(-3)(-3)\ne 27~\hspace{8em}(-3)(-3)(-3)=-27&#10;\\\\[-0.35em]&#10;\rule{34em}{0.25pt}\\\\&#10;\sqrt[3]{-125}\implies \sqrt[3]{-5^3}\implies -5\qquad because\qquad (-5)(-5)(-5)=-125&#10;\\\\\\&#10;however\qquad (5)(5)(5)\ne -125~\hspace{10em}(5)(5)(5)=125


so, when the root is an odd root, you will always get only one number that will produce the radicand.

6 0
3 years ago
Out of 25.050 20.505 25.005 20.055 what number is in thrird place
r-ruslan [8.4K]
If you are going from least to greatest, it is 25.005, but if you are going from greatest to least, it is 20.505 .
Hope I helped
7 0
2 years ago
The sum of a number times 6 and 21 is at least 24. <br> what's the inequality
Alex777 [14]

Answer:

x ≥ 1/2

Step-by-step explanation:

6x + 21 ≥ 24

6x ≥ 3

x ≥ 1/2

check: (1/2 x 6) + 21 = 24

4 0
2 years ago
12962 + 24% of (101250-84200)
Nikitich [7]

Answer:

17,054

Step-by-step explanation:

101250-84200= 17,050

24% of 17,050 is 4092

12962 + 4092 = 17,054

3 0
2 years ago
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