The polynomial a,b,c,are not perfect square polynomial and the polynomial d is perfect square polynomial.
The given polynomial is

What is the form of perfect square polynomial?

we solve this method by using perfect square method
add and subtract 1/9

factor 36

Now complete the square
Therefore this is not perfect square trinomial.
Similarly for

Complete square is,

This polynomial is also not perfect square trinomial.

complete square is,

This polynomial is not perfect square trinomial.

complete square is,

This polynomial is perfect square trinomial.
Therefore,
The polynomial a,b,c,are not perfect square polynomial and the polynomial d is perfect square polynomial.
To learn more about perfect square trinomial visit:
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The answer A because 2 weeks equal 14 days and so you divide 14 by 450 and get 30
Hello, I will try my best to explain this to you as simple as possible.
First, you have to pass the -4 to the other side, like this:
-3 1/2x - 4 = -38 1/8
↓
-3 1/2x = -38 1/8 - 4
Then, you have to subtract -4 from -38 1/8, like so:
-3 1/2x = -38 1/8 - 4
↓
-3 1/2x = -42 1/8
My preferred method for this next step is this:
-3 1/2x = -42 1/8
↓
-7/2x = 337/8
Then, we divide:
-7/2x = -42 1/8
↓
x = (-337/8) / (-7/2)
x = 12.0357142857
So, the answer is: 12.0357142857.
Hope this helped! c:
Answer
<span>D) Any point on a perpendicular bisector is equidistant from each endpoint of the line segment.
Explanation.
A perpendicular bisector, divides the line segment in to two equal parts. It should be perpendicular to the line segment.
The best description the </span><span>the construction of a perpendicular bisector is the one that talks of a general points that lies along the perpendicular bisector and are equidistant from the two ends. From the choices the answer is; </span><span>Any point on a perpendicular bisector is equidistant from each endpoint of the line segment.</span>