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alisha [4.7K]
2 years ago
10

Select the polynomial that is a perfect square trinomial. 36x2 − 4x 16 16x2 − 8x 36 25x2 9x 4 4x2 20x 25.

Mathematics
1 answer:
Naya [18.7K]2 years ago
3 0

The polynomial a,b,c,are not perfect square polynomial and the polynomial d is perfect square polynomial.

The given polynomial is

a) 36x^2-4x+16

What is the form of perfect square polynomial?

(ax+b)^2

we solve this method by using perfect square method

add and subtract 1/9

36x^2-4x+16+\frac{1}{9}-\frac{1}{9}

factor 36

\frac{143}{9}+36(x^2-\frac{x}{9}+\frac{1}{324} )

Now complete the square

\frac{143}{9}+36(x^2-\frac{1}{18})^2

Therefore this is not perfect square trinomial.

Similarly for

b) 16x^2-8x+36

Complete square is,

16(x-\frac{1}{4})^2+35

This polynomial is also not perfect square trinomial.

c) 25x^2+9x+4\\

complete square is,

25(x+\frac{9}{50})^2+\frac{319}{100}

This polynomial is not perfect square trinomial.

d)4x^2+20x+25\\

complete square is,

(2x+5)^2

This polynomial is perfect square trinomial.

Therefore,

The polynomial a,b,c,are not perfect square polynomial and the polynomial d is perfect square polynomial.

To learn more about perfect square trinomial visit:

brainly.com/question/1538726

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Answer:

\frac{3x^{4} }{2y^{4} }

Step-by-step explanation:

Factor out 7 from top and bottom :

\frac{7(3x^6y^5)}{7(2x^2y^9)}

Divide top and bottom by 7 :

\frac{3x^6y^5}{2x^2y^9}

Simplify :  

\frac{x^6}{x^4}=x^{2}

Simplify :

\frac{y^5}{y^9} = y^{-4}  = \frac{1}{y^{4} }

Collect everything together :

\frac{3x^{4} }{2y^{4} }

Hope this helped and have a good day

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Answer:

The mid-point (p + q , q + p) of AB is the same distance from the x-axis and the y-axis

Step-by-step explanation:

*<em> Lets explain how to solve the problem</em>

- Any point will be equidistant from the x-axis and the y-axis must have

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- Ex: point (4 , 4) is the same distance from the x-axis and the y-axis

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- If (x , y) is the mid-point of a segment its endpoints are

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* <em>Lets solve the problem</em>

∵ Point A has coordinates (p , q)

∵ Point B has coordinates (p + 2q , q + 2p)

- The mid-point of AB is (x , y)

∵ x=\frac{p+p+2q}{2}

∴ x=\frac{2p+2q}{2}

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∴ x=\frac{2(p+q)}{2}

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∴ x = p + q

∵ y=\frac{q+q+2p}{2}

∴ y=\frac{2q+2p}{2}

- Take 2 as a common factor from the terms of the numerator

∴ y=\frac{2(q+p)}{2}

- Divide up and down by 2

∴ y = q + p

∴ <em>The mid point of AB is (p + q , q + p)</em>

- p + q is the same with q + p

∵ The x-coordinate of the mid point of AB is p + q

∵ The y-coordinate of the mid point of AB is q + p

∵ p + q = q + p

∴ The coordinates of the mid-point of AB are equal

- According the explanation above

∴ The mid-point (p + q , q + p) of AB is the same distance from the

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