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3 years ago

The equations in this sytem were added to solve for x. What is the value of x?

Mathematics

2 answers:

son4ous [18]3 years ago

8 0

Question:

The equations in this system were added to solve for x. What is the value of x? -2x+y=8 5x-y=-5 3x=3

Options:

x = negative 3

x = negative 1

x = 1

x = 3

Answer:

The value of x is 1

Solution:

Given system of equations are:

-2x + y = 8 ------- eqn 1

5x - y = -5 ------- eqn 2

The above equations are added to solve for "x"

Add eqn 1 and eqn 2

-2x + y + 5x - y = 8 - 5

Combine the like terms

-2x + 5x + y - y = 3

Add the like terms

3x + 0 = 3

3x = 3

Divide both sides of equation by 3

x = 1

Thus the value of x is 1

igomit [66]3 years ago

3 0

Answer:

x=1

Step-by-step explanation:

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3 years ago

9/20

NISA [10]

For this case we must find the solution of the following quadratic equation:

$x ^ 2 + 5x + 7 = 0$

Where:

$a = 1\\b = 5\\c = 7$

Then, the solution is given by:

$x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}$

Substituting the values:

$x = \frac {-5 \pm \sqrt {5 ^ 2-4 (1) (7)}} {2 (1)}\\x = \frac {-5 \pm \sqrt {25-28}} {2}\\x = \frac {-5 \pm \sqrt {-3}} {2}$

By definition we have: $i ^ 2 = -1$

$x = \frac {-5 \pm \sqrt {3i ^ 2}} {2}\\x = \frac {-5 \pm i \sqrt {3}} {2}$

Thus, we have two complex roots.

Answer:

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