The equations in this sytem were added to solve for x. What is the value of x?

Mathematics

2 answers:

son4ous [18]2 years ago

8 0

Question:

The equations in this system were added to solve for x. What is the value of x? -2x+y=8 5x-y=-5 3x=3

Options:

x = negative 3

x = negative 1

x = 1

x = 3

Answer:

The value of x is 1

Solution:

Given system of equations are:

-2x + y = 8 ------- eqn 1

5x - y = -5 ------- eqn 2

The above equations are added to solve for "x"

Add eqn 1 and eqn 2

-2x + y + 5x - y = 8 - 5

Combine the like terms

-2x + 5x + y - y = 3

Add the like terms

3x + 0 = 3

3x = 3

Divide both sides of equation by 3

x = 1

Thus the value of x is 1

igomit [66]2 years ago

3 0

Answer:

x=1

Step-by-step explanation:

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Solve: a.x3+x2-8x - 12x+2 b. x3-4x2-3x + 18x-3 c. x2 + 4x + 4 d. x2 - 6x + 9

NeTakaya

<h2>Steps:</h2>

So firstly, this function is asking us to divide f(x) by g(x) so let's set that up as such:

$(\frac{f}{g})(x)=\frac{x^2-x-6}{1}\div \frac{x-3}{x+2}$

Next, remember that dividing by a number is the same as multiplying by its reciprocal. To find the reciprocal of a number, flip the numerator and denominator around. With this info, flip the second fraction to it's reciprocal and change the sign to multiplication:

$(\frac{f}{g})(x)=\frac{x^2-x-6}{1}\times \frac{x+2}{x-3}$

Next, we are going to factor x² - x - 6. Firstly, what two terms have a product of -6x² and a sum of -x? That would be -3x and 2x. Replace -x with 2x - 3x:

$(\frac{f}{g})(x)=\frac{x^2+2x-3x-6}{1}\times \frac{x+2}{x-3}$