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TiliK225 [7]
2 years ago
15

Need help plz on number 2

Mathematics
1 answer:
Inga [223]2 years ago
7 0

Answer is 5

Step-by-step explanation:

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madam [21]

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14

Step-by-step explanation:

you can simplify it by turning a²+b²/a-b

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Tpy6a [65]

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The limit as h approaches 0 of (e^(2+h)-e^2)/h is ?
Whitepunk [10]
<span>If you plug in 0, you get the indeterminate form 0/0. You can, therefore, apply L'Hopital's Rule to get the limit as h approaches 0 of e^(2+h),
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</span><span>so in the limit, as h goes to 0, you'll notice that the numerator and denominator each go to zero (e^h goes to 1, and so e^h-1 goes to zero). This means the form is 'indeterminate' (here, 0/0), so we may use L'Hoptial's rule:
</span><span>
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