Question

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Answer 1

Answer:

The kinetic energy of the object at a speed of 2 meters per second is 20 joules.

Explanation:

From the definition of the kinetic energy we get that kinetic energy is directly proportional to the square of the linear velocity. That is:

$K \propto v^{2}$

$K = k\cdot v^{2}$

Where:

$K$ - Kinetic energy, measured in joules.

$k$ - Proportionality constant, measured in joules per square meter per square second.

$v$ - Speed, measured in meter per second.

Now we can determine the kinetic energy by using the following extrapolation:

$\frac{K_{B}}{K_{A}} = \left(\frac{v_{B}}{v_{A}} \right) ^{2}$

$K_{B} = K_{A}\cdot \left(\frac{v_{B}}{v_{A}} \right)^{2}$

If we know that $K_{A} = 5\,J$, $v_{A} = 1\,\frac{m}{s}$ and $v_{B} = 2\,\frac{m}{s}$, the kinetic energy is:

$K_{B} = (5\,J)\cdot \left(\frac{2\,\frac{m}{s} }{1\,\frac{m}{s} } \right)^{2}$

$K_{B} = 20\,J$

The kinetic energy of the object at a speed of 2 meters per second is 20 joules.