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Firlakuza [10]
3 years ago
14

​40/​79−162.5%= whats the answer.

Mathematics
1 answer:
ozzi3 years ago
8 0
-1.118670886075949 is your answer.
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Which of the following is equvalent to (16^3/2)^1/2<br>A. 6<br>B. 8<br>C. 12<br>D. 64
bagirrra123 [75]
B. 8 is the answer.

Simplify to 2^4^(3/4) then 2^3 then that simplies to 8
6 0
3 years ago
Read 2 more answers
A medical researcher wondered if there is a significant difference between the mean birth weight of boy and girl babies. Random
Yuliya22 [10]

Answer:

b) independent samples t-test

t=\frac{(5.92 -5.74)-(0)}{\sqrt{\frac{1.88^2}{5}}+\frac{1.81^2}{5}}=0.154  

p_v =2*P(t_{8}>0.154) =0.881  

So with the p value obtained and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (boys) is NOT significantly different than the mean for the group 2 (Girls).  

Step-by-step explanation:

The system of hypothesis on this case are:  

Null hypothesis: \mu_1 = \mu_2  

Alternative hypothesis: \mu_1 \neq \mu_2  

Or equivalently:  

Null hypothesis: \mu_1 - \mu_2 = 0  

Alternative hypothesis: \mu_1 -\mu_2\neq 0  

Our notation on this case :  

n_1 =5 represent the sample size for group 1  

n_2 =5 represent the sample size for group 2  

We can calculate the mean and deviation for eaach group with the following formulas:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

\bar X_1 =5.92 represent the sample mean for the group 1  

\bar X_2 =5.74 represent the sample mean for the group 2  

s_1=1.88 represent the sample standard deviation for group 1  

s_2=1.81 represent the sample standard deviation for group 2  

If we see the alternative hypothesis we see that we are conducting a bilateral test and with independnet samples t test.

b) independent samples t-test

The statistic is given by this formula:  

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{\sqrt{\frac{s^2_1}{n_1}}+\frac{S^2_2}{n_2}}  

And now we can calculate the statistic:  

t=\frac{(5.92 -5.74)-(0)}{\sqrt{\frac{1.88^2}{5}}+\frac{1.81^2}{5}}=0.154  

The degrees of freedom are given by:  

df=5+5-2=8

And now we can calculate the p value using the altenative hypothesis:  

p_v =2*P(t_{8}>0.154) =0.881  

So with the p value obtained and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (boys) is NOT significantly different than the mean for the group 2 (Girls).  

7 0
3 years ago
27x39 Plz help jk jk
lesya [120]

Answer: 1053

Step-by-step explanation: ...............................

8 0
2 years ago
How do you subtract 42 minutes from 1 hour ,25 minutes.explain what to do and why you do it?
aksik [14]
So 1 hour= 60 minutes
60+25= 85 minutes
Now we should subtract the 42
85-42=43
3 0
2 years ago
Can someone help me question 17? Pls I really need how I can solve this question???
Anit [1.1K]
You can use the distance formula: d = sqrt((second x value - first x value)^2 + (second y value - first y value)^2):
answer : d = sqrt((3+2)^2+(6+6)^2) = 11.95826074 units
4 0
3 years ago
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