15-7=8
8×2=16
That's the answer
Answer:
A
They make the same amount - 20$ per hour
Step-by-step explanation:
200 / 10 = 20 dollars per hour
300 / 15 = 20 dollars per hour
ALSO TOM isn’t an option
HOPE THIS HELPS
PLZZ MARK BRAINLIEST
Answer:
$521.58 < μ < $666.1
Step-by-step explanation:
Spring break can be a very expensive holiday. A sample of 80 students is surveyed, and the average amount spent by students on travel and beverages is $593.84 at 92% confidence level. The sample standard deviation is approximately $369.34. Is $521.58 ≤μ≤ $666.10 correct?
Given that:
number of samples (n) = 80 students, mean (μ) = $593.84, standard deviation (σ) = $369.34, confidence level (c) = 92% = 0.92.
α = 1 - c = 1 - 0.92 = 0.08
![\frac{\alpha }{2} =\frac{0.08}{2} = 0.04](https://tex.z-dn.net/?f=%5Cfrac%7B%5Calpha%20%7D%7B2%7D%20%3D%5Cfrac%7B0.08%7D%7B2%7D%20%3D%200.04)
the z score of 0.46 (0.5 - 0.04) is the same as the z score of 0.04. This is gotten from the Normal Distribution Table.
Therefore, ![z_{\frac{\alpha }{2} }=z_{0.04}=1.75](https://tex.z-dn.net/?f=z_%7B%5Cfrac%7B%5Calpha%20%7D%7B2%7D%20%7D%3Dz_%7B0.04%7D%3D1.75)
The margin of error (e) is given as:
![e=z_{0.04}\frac{\sigma}{\sqrt{n} }=1.75*\frac{369.34}{\sqrt{80} } =72.26](https://tex.z-dn.net/?f=e%3Dz_%7B0.04%7D%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%20%7D%3D1.75%2A%5Cfrac%7B369.34%7D%7B%5Csqrt%7B80%7D%20%7D%20%20%3D72.26)
The confidence interval = (μ - e, μ + e) = ($593.84 - $72.26, $593.84 + $72.26) = ($521.58, $666.1)
The confidence interval is $521.58 < μ < $666.1
Answer:C
Step-by-step explanation:
The vertical line test