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Anvisha [2.4K]
3 years ago
6

IM having a bad day help pleaseeeee

Mathematics
1 answer:
alisha [4.7K]3 years ago
7 0
There would be no way to solve unless the distance between them was discussed
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Amber is making a scale drawing of a movie screen. The actual dimensions of a movie screen in her local theater are 60 ft wide a
Annette [7]

Answer:

3 inches  

60x = 9 x 20

60x = 180

x = 3        

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Round 7.224 is to the nearest hundredth.
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7.22 because the number 4 is not larger than 5 5 so it does not go up.

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Step-by-step explanation:

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4 years ago
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Let l(x) be the statement "x has an Internet connection" and C(x, y) be the statement "x and y have chatted over the Internet,"
Bas_tet [7]

The question is:

Let l(x) be the statement "x has an Internet connection" and C(x, y) be the statement "x and y have chatted over the Internet," where the domain for the variables x and y consists of all students in your class. Use quantifiers to express each of these statements.

a. Jerry does not have an Internet connection.

b. Rachel has not chatted over the Internet with Chelsea.

c. Jan and Sharon have never chatted over the Internet.

d. No one in the class has chatted with Bob.

e. Sanjay has chatted with everyone except Joseph.

f. Someone in your class does not have an Internet connection.

g. Not everyone in your class has an Internet connection.

h. Exactly one student in your class has an internet connection.

i. Everyone except one student in your class has an Internet connection.

j. Everyone in your class with an Internet connection has chatted over the Internet with at least one other student in your class.

k. Someone in your class has an Internet connection but has not chatted with anyone else in your class.

l. There are two students in your class who have not chatted with each other over the Internet.

m. There is a student in your class who has chatted with everyone in your class over the Internet.

n. There are at least two students in your class who have not chatted with the same person in your class.

o. There are two students in the class who between them have chatted with everyone else in the class.

Step-by-step explanation:

Note that: Because the arguments are variables, we write

Ix = I(x)

Cxy = C(x,y)

a. Jerry does not have an Internet connection.

~I(Jerry).

b. Rachel has not chatted over the internet with Chelsea.

~C(Rachel,Chelsea).

c. Jan and Sharon have never chatted over the internet.

~C(Jan,Sharon).

d. No one in the class has chatted with Bob.

~∃x C(x, Bob).

e. Sanjay has chatted with everyone except Joseph.

∀y (y ≠ Joseph → C(Sanjay, y)).

f. Someone in your class does not have an internet connection.

∃x ~Ix.

g. Not everyone in your class has an internet connection.

~∀x Ix.

h. Exactly one student in your class has an internet connection.

∃x (Ix ∧ ∀y (Iy → y = x)).

i. Everyone except one student in your class has an internet connection. This means exactly one student does not have a connection.

∃x (~Ix∧ ∀y (Iy → y = x)).

j. Everyone in your class with an internet connection has chatted over the internet with at least one other student in your class.

∀x (Ix → ∃y (Cxy ∧ x ≠ y)).

Assuming nobody can chat with him or herself, then

∀x (Ix → ∃y (Cxy))

k. Someone in your class has an internet connection but has not chatted with anyone else in your class.

∃x (Ix ∧ ∀y ~Cxy).

l. There are two students in your class who have not chatted with each other over the internet.

∃x ∃y (x ≠ y∧~Cxy).

m. There is a student in your class who has chatted with everyone in your class over the internet.

∃x ∀y Cxy.

n. There are at least two students in your class who have not chatted with the same person in your class. ∃x ∃y (x ≠ y ∧ ∃z (~Cxz ∧ ~Cyz)).

o. There are two students in the class who between them have chatted with everyone else in the class.

∃x ∃y (x ≠ y ∧ ∀z (Cxz ∨ Cyz)).

5 0
4 years ago
A STORY OF UNITS
Aleks04 [339]

Answer:

<em>$40 </em>will be the total cost of the ribbon.

Step-by-step explanation:

To find the cost of ribbon to be put on the edges of rectangular banner, we need to:

1. Find the perimeter of the rectangle.

2. Multiply the perimeter with the per foot cost to find the total cost.

Let us find the perimeter first:

Perimeter of a rectangle is given as:

P = 2 \times \text{(length+width)}

Here, the dimensions of rectangle are 4ft by 6ft.

So, perimeter = 2 \times (4+6) \Rightarrow 20\ ft

It is given that per foot cost is $2.

Total cost of the ribbon = 2 \times 20 \Rightarrow $40

<em>$40 </em>will be the total cost of the ribbon.

7 0
4 years ago
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