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IceJOKER [234]
3 years ago
8

Identifying the Property of Equality

Mathematics
2 answers:
arsen [322]3 years ago
7 0

Answer:

3 + x = 27

✔ subtraction property of equality with 3

x over 6  = 5

✔ multiplication property of equality with 6

Iteru [2.4K]3 years ago
3 0

Answer:

a) Compatibility of Equality with Addition, b) Compatibility of Equality with Multiplication

Step-by-step explanation:

a) This expression can be solved by using the Compatibility of Equality with Addition, that is:

1) 3+x = 27 Given

2) x+3 = 27 Commutative property

3) (x + 3)+(-3) = 27 +(-3) Compatibility of Equality with Addition

4) x + [3+(-3)] = 27+(-3) Associative property

5) x + 0 = 27-3 Existence of Additive Inverse/Definition of subtraction

6) x=24 Modulative property/Subtraction/Result.

b) This expression can be solved by using the Compatibility of Equality with Multiplication, that is:

1) \frac{x}{6} = 5 Given

2) (6)^{-1}\cdot x = 5 Definition of division

3) 6\cdot [(6)^{-1}\cdot x] = 5 \cdot 6 Compatibility of Equality with Multiplication

4) [6\cdot (6)^{-1}]\cdot x = 30 Associative property

5) 1\cdot x = 30 Existence of multiplicative inverse

6) x = 30 Modulative property/Result

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kaheart [24]

Answer:

24

Step-by-step explanation:

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If the opposite angle is 30, the hypotenuse is double the small side.

XZ=XW=2·12=24

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3 years ago
288 miles on 12 gallons of fuel; 240 miles on 10 gallons of fuel
Arisa [49]
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A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th
oksian1 [2.3K]

Answer:

17 seconds

Step-by-step explanation:

Solution:-

The trajectory of a rocket launched is modeled by a parabolic path via a quadratic equation as follows:

                               y = -16x^2 + 266x +102

Where,

                   y: The height of the rocket from ground

                   x: The time taken since rocket launch

We are to determine the time ( x ) it takes for the rocket to hit the ground. This can be determined by setting the quantity ( y ) to zero as follows

                             y = -16x^2 + 266x +102 = 0\\\\ -16x^2 + 266x +102 = 0

solve the quadratic equation using quadratic formula as follows:

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Answer: Ignore the negative value for time " -0.375 ". Hence, the rocket hits the ground at time t = 17 seconds

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