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faltersainse [42]

2 years ago

8

robyn has 3 pans to bake brownies for her friend she pours 1/4 cup of chocolate chips into each pan how much chocolate chips doe

s she need in all

2 answers:

valkas [14]2 years ago

4 0

Answer:

3/4 cups of choclate chips

Step-by-step explanation:

1/4+1/4+1/4=3/4

Marta_Voda [28]2 years ago

3 0

Answer:

3/4

Step-by-step explanation:

If she has 3 pans and pours 1/4 in each that's 3/4

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1/4+x=5 1/8<br> What is x?<br> Please, Please, Please, Please help me!<br> Will mark Brainliest!

miv72 [106K]

Answer:

4 7/8

Step-by-step explanation:

First we need to gte the denominators the same!

So we multiply the 1/4 by 2

1/4 x 2 = 2/8

Now we subtract the 2/8 from 5 1/8 to get our answer :)

5 1/8 - 2/8 = 4 7/8

Your final answer will be 4 7/8 :)

Have a great day!

Please rate and mark brainliest!

3 0

2 years ago

Ella was paid an 11 percent commission on the pair of shoes that she sold. The department store had paid $25 wholesale for the s

xxMikexx [17]

Answer:

The answer is B. $3.85.

Step-by-step explanation:

This is because, first if we get the percentage that the shoes were marked up by, we get that they were marked up to $35, because 40% of $25 is $10 and $25 + $10 = $35.

Then, we find the percentage of $35 that she earned. In order to do this, we see what 11% of $35 is. We get $3.85, because 10% of $35 is $3.50, and 1% of $35 is $0.35. $3.50 + $0.35 = $3.85.

This is why the answer is B. $3.85.

7 0

2 years ago

Read 2 more answers

What is the solution to 4x^3 – 3x^2 – 7x < 0? A. (–ꝏ, –1) U (0, 1.75) B. (–ꝏ, –1] U [0, 1.75] C. (–1, 0) U (1.75, ꝏ) D. [–1,

Nataly_w [17]

The answer is the third one

7 0

2 years ago

Read 2 more answers

When 258 college students are randomly selected and surveyed, it is found that 106 own a car. Find a 99% confidence interval for

juin [17]

Answer: 0.332 < p < 0.490

Step-by-step explanation:

We know that the confidence interval for population proportion is given by :-

$\hat{p}\pm z^*\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

, where n= sample size

$\hat{p}$ = sample proportion

z* = critical z-value.

As per given , we have

n= 258

Sample proportion of college students who own a car = $\hat{p}=\dfrac{106}{258}\approx0.411$

Critical z-value for 99% confidence interval is 2.576. (By z-table)

Therefore , the 99% confidence interval for the true proportion(p) of all college students who own a car will be : $0.411\pm (2.576)\sqrt{\dfrac{0.411(1-0.411)}{258}}\\\\=0.411\pm (2.576)\sqrt{0.00093829}\\\\= 0.411\pm (2.576)(0.0306315197142)\\\\=0.411\pm 0.0789=(0.411-0.0789,\ 0.411+0.0789)\\\\=(0.3321,\ 0.4899)\approx(0.332,\ 0.490)$

Hence, a 99% confidence interval for the true proportion of all college students who own a car : 0.332 < p < 0.490

3 0

2 years ago

If a house is 15m long and 12m wide how long is the diagonal of the house

Nitella [24]

If this talks about the diagonal of the flooring then it is 9m

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2 years ago