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faltersainse [42]
2 years ago
8

robyn has 3 pans to bake brownies for her friend she pours 1/4 cup of chocolate chips into each pan how much chocolate chips doe

s she need in all
Mathematics
2 answers:
valkas [14]2 years ago
4 0

Answer:

3/4 cups of choclate chips

Step-by-step explanation:

1/4+1/4+1/4=3/4

Marta_Voda [28]2 years ago
3 0

Answer:

3/4

Step-by-step explanation:

If she has 3 pans and pours 1/4 in each that's 3/4

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HELP! IM STUCK!
Readme [11.4K]

Answer:

(x-1)^2+(y+4)^2=9

Step-by-step explanation:

The equation of a circle is given by:

(x-h)^2+(y-k)^2=r^2

Where (h, k) is the center and r is the radius.

The center of the circle is (1, -4).

And the radius is 3.

Substitute:

(x-(1))^2+(y-(-4))^2=(3)^2

Simplify. Thus, our equation is:

(x-1)^2+(y+4)^2=9

3 0
3 years ago
N =⟨−2,  −1⟩ and D=<img src="https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-3%260%5C%5C4%261%5C%5C%5Cend%7Barray%
zepelin [54]

Answer:

6

-9

Step-by-step explanation:

-3(-2) + 0(-1)

4(-2) + 1(-1)

6 + 0

-8 + -1

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*don't forget to add brackets on each side of every calculation okay :)

5 0
3 years ago
CAN ANYBODY HELP ME OUT
bija089 [108]

Answer:

Correct option is

b. If two sides and one included angle are equal in triangles PQS and PRS, then their corresponding sides are also equal.

Step-by-step explanation:

Here, we are given the line RQ, which is divided in two equal parts by a line PS which is perpendicular to RQ.

The foot S of PS is on the line RQ.

First of all, let us do a construction here.

Join the point R with P and P with Q.

Please refer to the attached image.

Now, let us consider the triangles  PQS and PRS:

  • Side QS = RS (as given)
  • \angle PSR = \angle PSQ = 90^\circ
  • Side PS = PS (Common side in both the triangles)

Now, Two sides and the angle included between the two triangles are equal.

So by SAS congruence we can say that \triangle PRS \cong \triangle PQS

Therefore, the corresponding sides will also be equal.

RP = QP

RP is the distance between R and P.

QP is the distance between Q and P.

Hence, to prove that P is equidistant from R and Q, we have proved that:

b. If two sides and one included angle are equal in triangles PQS and PRS, then their corresponding sides are also equal.

7 0
2 years ago
A certain pet store sells only dogs and cats. In
Leona [35]
They sold 300 dogs and 200 cats
6 0
2 years ago
It appears that the derivatives of sine and cosine are related. What about the second derivatives?.
Andru [333]

Answer:

Step-by-step explanation:

\frac{d}{dx} (sin~x)=cos~x\\\frac{d}{dx}(cos~x) =-sin~x\\\frac{d^2}{dx^2} (sin~x)=\frac{d}{dx} (cos~x)=- sin~x\\\frac{d^2}{dx^2} (cos~x)=\frac{d}{dx} (-sin~x)=-cos~x

5 0
2 years ago
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