Order from least to greatest, please.

The hire purchase price of a fridge is 16400. 25% is paid as deposit, the rest is spread over 12 equally monthly instalments. If

Flauer [41]

Answer: a. 13120

b. 4100

c. 1025

d. 3280

Step-by-step explanation:

(a) find the costs price of the fridge

Since the cash price is 20% less the hire purchase price, then the cost of the fridge will be:

= (100% - 20%) × 16400

= 80% × 16400

= 0.8 × 16400

= 13120

(b) calculate the deposit

Since 25% is paid as deposit, the deposit will be:

= 25% × 16400

= 0.25 × 16400

= 4100

(c) what is the monthly installments

Monthly installments will be:

= (16400 - 4100)/12

= 12300/12

= 1025

(d) what is the differences between the cash price and the hire purchase price.

This will be:

Hire purchase price = 16400

Cash price = 13120

= 16400 - 13120

= 3280

3 0

3 years ago

X+8y/4=9y solve for x

Cerrena [4.2K]

If the 8y/4 is the only fraction, the answer is x=7y

If the whole input of the equation is in a fraction, the answer is x=28y

:)

4 0

2 years ago

Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round y

kupik [55]

Answer:

75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5 pounds.

Step-by-step explanation:

The question is missing. It is as follows:

Adult wild mountain lions (18 months or older) captured and released for the first time in the San Andres Mountains had the following weights (pounds): 69 104 125 129 60 64

Assume that the population of x values has an approximately normal distribution.

Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round your answers to one decimal place.)

75% Confidence Interval can be calculated using M±ME where

M is the sample mean weight of the wild mountain lions ( $\frac{69 +104 +125 +129+60 +64}{6} =91.8$ )

ME is the margin of error of the mean

And margin of error (ME) of the mean can be calculated using the formula

ME= $\frac{t*s}{\sqrt{N} }$ where

t is the corresponding statistic in the 75% confidence level and 5 degrees of freedom (1.30)

s is the standard deviation of the sample(31.4)

N is the sample size (6)

Thus, ME= $\frac{1.30*31.4}{\sqrt{6} }$ ≈16.66

Then 75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5

3 0

2 years ago

All I have to do is fill in the blanks and I'm a bit confused on what to do. Could someone please help!!

lbvjy [14]

Jeremy and Randell are brothers and each are trying to raise money for summer camp.
To help Jeremy raise money, his parents told him he could wash each of their cars once a week for $20.00 each. He has already earned $640.00. The football camp that he wants to attend costs $1,469.00.
To help Randell raise money, his parents told him he could mow the grass for them and both sets of grandparents once every 2 weeks and earn $28.00 for each lawn he mows. He has already earned $728.00. The lacrosse camp that he wants to attend costs $1,701.00.
If Jeremy and Randell each earn enough money to attend the camps of their choice, then from this point on (randell) needs to complete (idk what would got here) more chores than(jeremy)

is it asking you to fill in the blanks with their names if so i think it would be this.

6 0

2 years ago

All 231 students in math club went on a field trip some rode in vans that held 7 people and some rode on buses that held 25 peop

MariettaO [177]

Answer:

8 vans

7 buses

Step-by-step explanation:

Let there be "b" buses

and "v" vans

Since 7 people is the capacity of vans, the total capacity is

7v

Also, since 25 people is the capacity of 1 bus, the total capacity is

25b

In total 231 people, so we can write our first equation as:

7v + 25b = 231

Now, we know there are 15 vehicles (bus + vans) in total, so we can write our 2nd equation as:

v + b = 15

Now, we solve for v and b. Let's solve the 2nd equation for v and substitute that into 1st and solve for b first:

v + b = 15

v = 15 - b

Now,

$7v + 25b = 231\\7(15-b) + 25b = 231\\105-7b+25b=231\\18b=126\\b=7$

Hence, there are 7 buses

Since 15 vehicles in total, the number of vans is:

15 - 7 = 8 vans

So,

8 vans

7 buses

8 0

3 years ago