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3 years ago

-2x-3y-5z=24 -3x-6y-4z=20 -x-6y+6z=-26

Mathematics

1 answer:

earnstyle [38]3 years ago

5 0

Answer equals to - 14

Step-by-step explanation:

6 plus 6 equals to 12

-26 minus 12 equals to -14

Therefore answer equals to minus 14

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HELP PLEASE 100 POINTS

frosja888 [35]

Answer:

Step-by-step explanation:

That's an awful lot of points. You don't have to give that many. 10 or 15 points would be more than enough.

The graph touches the x axis at 1 point. That means its basic formula is y = (x - a)^2

Since it upside down, the formula is y = -(x - a)^2. A couple of other things are true.

a = 1 because that's where the graph touches the x axis. y = - x^2 has shifted 1 unit to the right.

Finally the y intercept is -4 which means that the final equation is y = -4(x-1)^2

That's all preliminary. The actual question is, what does the discriminate look like?

y = -4(x^2 - 2x + 1)

y = -4x^2 + 8x - 4

a = - 4

b = 8

c = - 4

sqrt(b^2 - 4ac)

sqrt(8^2 - 4(-4)(-4) )

sqrt(64 - 64) = 0

The answer is the third one. The answer will always be 0 when the graph touches the x axis and does not go through it.

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3 years ago

Converse statement. If this month is February then the next month is march

Shkiper50 [21]

Answer:

If the month is march then the next month is February

Step-by-step explanation:

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3 years ago

When driving in England, Brian drove through several speed cameras. On one drive, Brian left his hotel and after 7 minutes he wa

DedPeter [7]

Solution :

The formula for the linearization of a function $f(x)$ at a point $x$ = a is given as

$L(x)=f(a)+(x-a)f'(a)$

Assuming the time is t and the distance travelled is $f(t)$ , that makes the speed as $f'(t)$ .

So substituting them in the linearization formula,

A. At t = 7 minutes

f(7) = 2.5 km

f'(7) = 0.5 kpm

∴ $L_7(t)=f(7)+(t-7)f'(7)$

$=2.5+(t-7)0.5$

$=2.5+0.5t-3.5$

$=0.5t-1$

B. At t = 18 minutes

f(18) = 14.8 km

f'(18) = 0.8 kpm

∴ $L_{18}(t)=f(18)+(t-18)f'(18)$

$=14.8+(t-18)0.8$

$=14.8+0.8t-14.4$

$=0.8t-0.4$

C. Substituting the value of t as 14 in both the linearization to determine the position at 14 minutes, we get

$L_7(14)=0.5(14)-1.0$

= 7 - 1

= 6 km

$L_{18}(14)=0.8(14)+0.4$

= 11.2 + 0.4

= 11.6 km

D. According to the linearization at 7, the distance travelled between the 7 minutes and 14 minutes is = 6 km - 2.5 km

= 3.5 km

And between the 14 minutes and 18 minutes is = 14.8 km - 6 km

= 8.8 km

This is an average speed of 0.5 kpm in the first interval and an average speed of 2.2 kpm.

Now, according to the linearization of 18, the distance travelled between the 7 minutes and the 14 minutes is = 11.6 km - 2.5 km

= 9.1 km

And between 14 minutes and 18 minutes is = 14.8 km - 11.6 km

= 3.2 km

This gives an average speed of 1.3 kpm in the first interval and 0.8 kpm in the second interval.

Therefore, the second approximation is the better one since the average speed are closer to the actual readings in the second linearization.

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3 years ago

PLEASE ANSWER ASAP WILL MARK BRAINLIEST!!

nirvana33 [79]

Answer:

true

Step-by-step explanation:

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3 years ago

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If Anna pays $18 for a pack of 25 markers how much is each marker

gayaneshka [121]

18 / 25 = 0.72 per marker

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3 years ago