Answer:
(2, 8)
Step-by-step explanation:
There are a couple of different ways to do this, but I am going to use substitution since we already have one of those equations solved for y. If y=3x+2, then we can sub 3x+2 in for y in the other equation:
-3x + 2(3x + 2) = 10 and
-3x + 6x + 4 = 10 and
3x + 4 = 10 and
3x = 6 so
x = 2. Now that we know x = 2, we can sub a 2 in for x in either equation to solve for y:
y = 3x + 2 gives us, with the substitution, y = 3(2) + 2 so y = 8. The solution set is (2, 8)
64 = 4 x 4 x 4 g^3<span> = g x g x g the problem is the sum of of 2 cubes </span>8<span> = 2 x 2 x 2 so the </span>factored form<span> is - a</span>3+b3<span>=(a+b)(a2−ab+b2).</span>
Answer:
3×10^4
Step-by-step explanation:
The desired factor is found by calculating the ratio of the two numbers:
k = (9×10^2)/(3×10^-2) = (9/3)×10^(2 -(-2)) = 3×10^4
The first number is 3×10^4 = 30,000 times as much as the second number.
I don’t think there’s a solution
0.10d + 0.25q = 3.55
q = d + 3
0.10d + 0.25(d + 3) = 3.55
0.10d + 0.25d + 0.75 = 3.55
0.10d + 0.25d = 3.55 - 0.75
0.35d = 2.80
d = 2.80/0.35
d = 8.....8 dimes
q = d + 3
q = 8 + 3
q = 11 <=== 11 quarters
