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lorasvet [3.4K]
3 years ago
10

Plz help 20 points answers

Mathematics
1 answer:
zhannawk [14.2K]3 years ago
7 0

Answer:A-3rd box

B-first box

C-first box

D-middle box

Step-by-step explanation:

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Which system is equivalent to
Sergio [31]

Answer:

We can find the system equivalent to this one by replacing one of the equations with a multiply of itself, so:

Let’s multiply y = x-2 by 2

2y=2x-4

A system equivalent to this one is

y = -2x^2 (this remains the same)

2y= 2x-4

8 0
3 years ago
The sum of two numbers is 100, the difference between the two numbers is 26. What is the number that is less?
Zepler [3.9K]
The numbers that would be smaller would be the two with the difference of 26.
27-1=26 where as, if you were to use a 1 in each, 99+1= 100. Therefore 27 and 1 (28) is less than 99 and 1 (100).

6 0
3 years ago
6 - 8x = 6x - 9x + 11
mars1129 [50]

6-8x=-3x+11

-8x+3x=11-6

-5x=5

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6 0
3 years ago
Read 2 more answers
Today, everything at a store is on sale. The store offers a 20% discount.
lukranit [14]

Answer: A- x - 0.20x = 0.8x

Step-by-step explanation:

4 0
3 years ago
Find the inverse of ????−7 −2
Masja [62]

Answer:

A^{-1}=\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}

Step-by-step explanation:

A=\begin{bmatrix}-7 & -2\\ 4 & 1\end{bmatrix}

det\ A=-7\times 1-(-2)\times 4\\\Rightarrow det\ A=1

A^{-1}=\frac{1}{det\ A}\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}\\\Rightarrow A^{-1}=\frac{1}{1}\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}\\\Rightarrow A^{-1}=\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}

\therefore A^{-1}=\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}

A.A^{-1}=\begin{bmatrix}-7 & -2\\ 4 & 1\end{bmatrix}\times \begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}\\\Rightarrow A.A^{-1}=\begin{pmatrix}\left(-7\right)\cdot \:1+\left(-2\right)\left(-4\right)&\left(-7\right)\cdot \:2+\left(-2\right)\left(-7\right)\\ 4\cdot \:1+1\cdot \left(-4\right)&4\cdot \:2+1\cdot \left(-7\right)\end{pmatrix}\\\Rightarrow A.A^{-1}=\begin{pmatrix}1&0\\ 0&1\end{pmatrix}

Hence, confirmed

6 0
3 years ago
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