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Ghella [55]
4 years ago
13

(6.05)Out of 150 students at summer camp, 70 signed up for swimming. There were 25 that signed up for zip line, of which 12 of t

hose students also signed up for swimming. What percent of the students at camped signed up for neither swimming or the zip line? (5 points)
54%
45%
84%
67%
Mathematics
1 answer:
marishachu [46]4 years ago
7 0

Answer:

45% of the students at camped signed up for neither swimming or the zip line ⇒ 2nd answer

Step-by-step explanation:

To solve the problem let us use the following rules

n(swimming or zip line) = n(swimming) + n(zip line) - n(swimming and zip line)

n(neither) = n(total) - n(swimming or zip line)

∵ 70 signed up for swimming

∵ n(swimming) = 70

∵ There were 25 that signed up for zip line

∵ n(zip line) = 25

∵ 12 of those 25 students also signed up for swimming

∵ n(swimming and zip line) = 12

Use the 1st rule to find n(swimming or zip line)

∵ n(swimming or zip line) = 70 + 25 - 12

∴ n(swimming or zip line) = 83

∴ There were 83 students signed up in swimming or zip line

Use the 2nd rule to find n(neither)

∵ There were 150 students at summer camp

∴ n(total) = 150

∵ n(swimming or zip line) = 83

∴ n(neither) = 150 - 83

∴ n(neither) = 67

∴ There were 67 students signed up for neither swimming or the

   zip line

To find the percent of the neither divide n(neither) by n(total), then multiply the quotient by 100%

∵ %(neither) = \frac{67}{150} × 100%

∴ %(neither) = 44.6666667%

- Round it to the nearest whole number

∴ %(neither) = 45%

45% of the students at camped signed up for neither swimming or the zip line

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Step-by-step explanation:

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cross multiply to find the expression for x.

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$0.49x/$0.49  ≤  $3/$0.49

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The number of hamburgers you can buy is represented by the inequality x ≤  6.12

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The first derivative is
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       = x⁵(x-1)⁴(11x - 6)
The critical values are the zeros of f'(x). They are
x = 0, 6/11, and 1.
The critical values indicate that turning points exist for f(x) at the critical points. However, we do not know the nature of the turning points.

Write the first derivative in the form f'(x) = (x-1)⁴(11x⁶ - 6x⁵).
The second derivative is
f''(x) = 4(x-1)³(11x⁶ - 6x⁵) + (x-1)⁴(66x⁵ - 30x⁴)
        = (x-1)³(44x⁶ - 24x⁵ + 66x⁶ - 30x⁵ - 66x⁵ + 30x⁴)
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The graphs shown below confirm these results.

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