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kompoz [17]
3 years ago
9

A .12.25 unitsb .10 unitsc. 12.7 unitsd. 10.25 units​

Mathematics
1 answer:
wariber [46]3 years ago
7 0

Answer:

I don't know if i'm right but I think it's b.

Step-by-step explanation:

I am so sorry if I am wrong.

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For a standard normal distribution, find the approximate value of p (negative 0.78 less-than-or-equal-to z less-than-or-equal-to
topjm [15]

The approximate value of P(-0.78 ≤ Z ≤ 1.16) is obtained being 0.6593

<h3>How to get the z scores?</h3>

If we've got a normal distribution, then we can convert it to standard normal distribution and its values will give us the z score.

If we have  X \sim N(\mu, \sigma)

(X is following normal distribution with mean \mu and standard deviation \sigma)

then it can be converted to standard normal distribution as

Z = \dfrac{X - \mu}{\sigma}, \\\\Z \sim N(0,1)

(Know the fact that in continuous distribution, probability of a single point is 0, so we can write

P(Z \leq z) = P(Z < z) )

Also, know that if we look for Z = z in z-tables, the p-value we get is

P(Z \leq z) = \rm p \: value

For this case, we have to find:

P(-0.78\leq Z \leq 1.16)

It can be rewritten as:

P(-0.78\leq Z \leq 1.16) = P(Z \leq 1.16) - P(Z < -0.78) \\P(-0.78\leq Z \leq 1.16) = P(Z \leq 1.16) - P(Z \leq -0.78)

The p-values for Z = 1.16 and Z = -0.78 from the z-table is found as 0.8770 and 0.2177 respectively, and therefore, we get:

P(-0.78\leq Z \leq 1.16) = P(Z \leq 1.16) - P(Z \leq -0.78)\\P(-0.78\leq Z \leq 1.16) = 0.8770 - 0.2177 = 0.6593

Thus, the approximate value of P(-0.78 ≤ Z ≤ 1.16) is obtained being 0.6593

Learn more about z-score here:

brainly.com/question/21262765

8 0
2 years ago
Suppose Metro by T-Mobile wants to offer a simple extended warranty plan. If your phone is damaged, they will repair it for up t
MAXImum [283]

Answer:

45

Step-by-step explanation:

Given that :

Voucher awarded (x) :

Repair = $50

Lose or destroy = $200

P(x):

Replacement voucher = 5%

Repair voucher = 10%

X ______ 50 ______ 200

P(x) ____ 0.1 _______ 0.05

Expected variance Var(X) :

ΣX²p(x) - E(x) ;

E(x) = Σx*p(x) = (50*0.1) + (200*0.05) = 15

ΣX²p(x) = Σ[(50^2 * 0. 1) + (200^2 * 0.05)] = 250 + 2000 = 2250

Var(X) = 2250 - 15^2 = 2025

Standard deviation = √Var(x)

Standard deviation = √2025

Standard deviation = $45

4 0
3 years ago
Use the graph of the following function (x) to find the value. <br> f(1)
kvv77 [185]

From the graph of the given function , the value of f(1) = -1.

As given in the question,

From the graph of the given function,

Two coordinates from the graph are as follow:

( x₁ , y₁) = (1, -1)

( x₂ , y₂ ) = ( 0, -3 )

Equation of the line representing the function is given by:

(y - y₁) /(x-x₁) = ( y₂ -y₁)/ (x₂ -x₁)

⇒(y +1)/ (x-1) = (-3 +1)/ (0-1)

⇒ (y +1)/ (x-1) = 2

⇒y +1 = 2x -2

⇒ y = 2x -3

To get the value of x we have,

  y = f(x)

⇒f(x) = 2x -3

⇒f(1) = 2(1) -3

⇒f(1) = -1

Therefore, from the graph of the given function , the value of f(1) = -1.

Learn more about graph here

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#SPJ1

3 0
1 year ago
True or false: ) is a function.<br><br> f(x)<br> OA. True<br> OB. False
Dmitry [639]

Answer:

true that is the formula for a function

Step-by-step explanation:

5 0
3 years ago
Solve: 75(7-3)<br>with work shown​
anzhelika [568]

Answer:

300 is the solution

Step-by-step explanation:

use the distributive property

75 * 7 = 525

75 * -3 = -225

put em together

525 - 225 = 300

4 0
3 years ago
Read 2 more answers
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