Question

R1 R3 in an electric instrument called a Wheatstone bridge electric resistances are related byR1/R2=R3/R4. Find R 2 if R1 = 10.00 Ω R3-6470, and R2 = R4-15.0 . If necessary, round to two decimal places.

Answer 1

Answer:

R2 = 43.03 ohms

Step-by-step explanation:

If R2=R4-15, then R4 = R2+15

According to the Wheastone bridge equation we have:

$\frac{R1}{R2} =\frac{R3}{R4}\\\frac{10}{R2} =\frac{6470}{R2+15}\\\\10*(R2+15) = 6470*R2\\10*R2+150 = 6470*R2\\150=(6470-15)*R2\\R2=\frac{6455}{150}= 43.03333$