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3 years ago

There are 45 questions on your math exam. You answered 8/10 how many questions did you answer correctly?

Mathematics

2 answers:

emmasim [6.3K]3 years ago

8 0

Answer: 36 answers

Step-by-step explanation:

The given statement : There are 45 questions on your math exam. You answered 8/10.

i.e. The total number of questions in math exam = 45

The fraction question answered to the total questions= $\dfrac{8}{10}=\dfrac{2}{5}$

Now, the number of questions answered will be given by :-

$n=\dfrac{2}{5}\times45\\\\\Rightarrow\ n=36$

Hence, You answered 36 answers.

Dima020 [189]3 years ago

4 0

36 questions correctly

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The sum of x and it’s opposite is always zero?

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Answer:

1) Let's consider the first case with the number 0 the oppose is also 0 and we have that 0-0=0 so then applies

2) Now let's consider any real number a no matter positive or negative we will have that:

$a-a =0$

Or in the other case:

$-a -(-a) =-a +a=0$

So then we can conclude that the expression is a general rule and is true

Step-by-step explanation:

For this case we can verify if the following expression is true or false:

The sum of x and it’s opposite is always zero?

If we want to proof this we need to show that for any number is true.

1) Let's consider the first case with the number 0 the oppose is also 0 and we have that 0-0=0 so then applies

2) Now let's consider any real number a no matter positive or negative we will have that:

$a-a =0$

Or in the other case:

$-a -(-a) =-a +a=0$

So then we can conclude that the expression is a general rule and is true

5 0

3 years ago

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aksik [14]

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3 0

3 years ago

Can you please answer the question?

Roman55 [17]

The trigonometric expression $\frac{\tan^{2} \alpha}{\tan \alpha - 1} + \frac{\cot^{2} \alpha}{\cot \alpha - 1}$ is equivalent to the trigonometric expression $\sec \alpha \cdot \csc \alpha + 1$ .

<h3>How to prove a trigonometric equivalence</h3>

In this problem we must prove that one side of the equality is equal to the expression of the other side, requiring the use of algebraic and trigonometric properties. Now we proceed to present the corresponding procedure:

$\frac{\tan^{2} \alpha}{\tan \alpha - 1} + \frac{\cot^{2} \alpha}{\cot \alpha - 1}$

$\frac{\tan^{2}\alpha}{\tan \alpha - 1} + \frac{\frac{1}{\tan^{2}\alpha} }{\frac{1}{\tan \alpha} - 1 }$