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3 years ago

6

Value of sin^-1(sin 9pi/7)

1 answer:

mrs_skeptik [129]3 years ago

3 0

Hint: $\bf \begin{array}{llll}
sin^{-1}[sin(whatever)]= whatever\\\\
cos^{-1}[cos(whatever)]= whatever\\\\
tan^{-1}[tan(whatever)]= whatever
\end{array}\\\\
------------------\\\\
\begin{array}{llll}
sin[sin^{-1}(whatever)]= whatever\\\\
cos[cos^{-1}(whatever)]= whatever\\\\
tan[tan^{-1}(whatever)]= whatever
\end{array}$

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Need help ASAP with this question please

Assoli18 [71]

Answer:

4th option, 5 5/6

Step-by-step explanation:

8 1/2 - 2 2/3

= 17/2 - 8/3

= (51-16)/6

= 35/6

= 5 5/6

Answered by GAUTHMATH

6 0

3 years ago

Find the volume of the rectangular

Kobotan [32]

Answer:

Hope this will help you

Step-by-step explanation:

$volume \: of \: rectangular \: prism = l \times b \times h \\ = 0.6 ft\times 0.8 ft\times 3.8ft \\ = 1.824 {ft}^{3}$

4 0

2 years ago

Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse

Drupady [299]

Answer:

$a'(d) = \frac{d}{5} + \frac{3}{5}$

$a(a'(d)) = a'(a(d)) = d$

Step-by-step explanation:

Given

$a(d) = 5d - 3$

Solving (a): Write as inverse function

$a(d) = 5d - 3$

Represent a(d) as y

$y = 5d - 3$

Swap positions of d and y

$d = 5y - 3$

Make y the subject

$5y = d + 3$

$y = \frac{d}{5} + \frac{3}{5}$

Replace y with a'(d)

$a'(d) = \frac{d}{5} + \frac{3}{5}$

Prove that a(d) and a'(d) are inverse functions

$a'(d) = \frac{d}{5} + \frac{3}{5}$ and $a(d) = 5d - 3$

To do this, we prove that:

$a(a'(d)) = a'(a(d)) = d$

Solving for $a(a'(d))$

$a(a'(d)) = a(\frac{d}{5} + \frac{3}{5})$

Substitute $\frac{d}{5} + \frac{3}{5}$ for d in $a(d) = 5d - 3$

$a(a'(d)) = 5(\frac{d}{5} + \frac{3}{5}) - 3$

$a(a'(d)) = \frac{5d}{5} + \frac{15}{5} - 3$

$a(a'(d)) = d + 3 - 3$

$a(a'(d)) = d$

Solving for: $a'(a(d))$

$a'(a(d)) = a'(5d - 3)$

Substitute 5d - 3 for d in $a'(d) = \frac{d}{5} + \frac{3}{5}$

$a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}$

Add fractions

$a'(a(d)) = \frac{5d - 3+3}{5}$

$a'(a(d)) = \frac{5d}{5}$

$a'(a(d)) = d$

Hence:

$a(a'(d)) = a'(a(d)) = d$

7 0

2 years ago

Javier's parents set an amount of money aside when he was born. They earned 4.5% simple interest on that money each year. When J

solmaris [256]

Answer:

Javier's parents set aside $1500 when he was born

Step-by-step explanation:

This is a simple interest problem.

The simple interest formula is given by:

$E = P*I*t$

In which E is the interest earned, P is the principal(the initial amount of money), I is the interest rate(yearly, as a decimal) and t is the time.

In this question, we have that:

$E = 1012.50, t = 15, I = 0.045$

We have to find P. So

$E = P*I*t$

$1012.50 = P*15*0.045$

$P = \frac{1012.50}{15*0.045}$

$P = 1500$

Javier's parents set aside $1500 when he was born

6 0

3 years ago

What is the mean absolute deviation of the data set?<br> {12, 17, 12, 8,6)

ser-zykov [4K]

Answer:The mean absolute deviation of the set of data is

2.24

.

Step-by-step explanation:

8 0

2 years ago