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Reika [66]
3 years ago
13

Select the sample most representative of the population of interest. The Director of Food Operations at a small college campus w

ants to determine student concerns about cafeteria food. A. A randomly selected group of 30 students entering the dining hall before dinner B. A randomly selected group of 30 registered students C. A randomly selected group of 30 students who have signed food contracts D. A randomly selected group of 30 students leaving the dining hall after dinner
Mathematics
1 answer:
Sati [7]3 years ago
8 0

Answer:

D. A randomly selected group of 30 students leaving the dining hall after dinner

Correct since the students who had dinner can talk about the cafeteria food and we can determine the concerns since they are using the cafeteria.  

Step-by-step explanation:

They want to determine student concerns about cafeteria food, that's the objective in the study

Let's analyze one by one the possible options

A. A randomly selected group of 30 students entering the dining hall before dinner

False, a person not dinner then can't talk about the caefeteria with accuracy since is not using the service yet.

B. A randomly selected group of 30 registered students

False, we are focused on the people who assit to the cafateria, and we can have people who not use the caefeteria in the sample and that's not the interest.

C. A randomly selected group of 30 students who have signed food contracts

False, a person could be signed a food contract but can no assist to the cafeteria in some cases.

D. A randomly selected group of 30 students leaving the dining hall after dinner

Correct since the students who had dinner can talk about the cafeteria food and we can determine the concerns since they are using the cafeteria.  

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Let D be the mid point of side BC, [B(2, - 1), C(5, 2)].

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D = ( \frac{2 + 5}{2},  \:  \:  \frac{ - 1 + 2}{2} ) = ( \frac{7}{2}, \:  \:  \frac{ 1}{2} ) \\ \therefore D= (3.5, \:  \: 0.5) \\  \& \: A=(-1,\:\:4)...(given) \\\\  now \: by \: distance \: formula \\  \\ Length  \: of \:  segment  \: AD \\  =  \sqrt{( - 1 - 3.5)^{2}  +  {(4 - 0.5)}^{2} }  \\ =  \sqrt{(4.5)^{2}  +  {(3.5)}^{2} }  \\ =  \sqrt{20.25 + 12.25 }  \\  =  \sqrt{32.5}  \\    \red{ \boxed{\therefore Length  \: of \:  segment  \: AD  = 5.7 \: units}}

4 (a)

Equation of line AB[A(2, 1), B(-2, - 11)] in two point form is given as:

\frac{y-y_1}{y_1-y_2} =\frac{x-x_1}{x_1 - x_2} \\\\\therefore \frac{y-1}{1-(-11)} =\frac{x-2}{2 - (-2) } \\\\\therefore \frac{y-1}{1+11} =\frac{x-2}{2 +2} \\\\\therefore \frac{y-1}{12} =\frac{x-2}{4} \\\\\therefore \frac{y-1}{3} =\frac{x-2}{1} \\\\\therefore y-1= 3(x - 2)\\\\\therefore y= 3x - 6+1\\\\\therefore y= 3x - 5\\\\ \huge \purple {\boxed {\therefore 3x - y-5=0}} \\

is the equation of line AB.

Now we have to check whether C(4, 7) lie on line AB or not.

Let us substitute x = 4 & y = 7 on the Left hand side of equation of line AB and if it gives us 0, then C lies on the line.

LHS = 3x - y-5\\=3\times 4-7-5\\= 12-12\\=0\\= RHS

Hence, point C (4, 7) lie on the straight line AB.

4(b)

Like we did in 4(a), first find the equation of line AB and then substitute the coordinates of point C in equation and if they satisfy the equation, then all the three points lie on the straight line.

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