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Tresset [83]
3 years ago
5

If a − b ∈ P, then (a + c) − (b + c) = a − b is in P. Thus a + c > b + c​

Mathematics
1 answer:
DochEvi [55]3 years ago
4 0

Answer:

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Step-by-step explanation:

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In a sample of 60 electric motors, the average efficiency (in percent) was 85 and the standard deviation was 2. Section 05.01 Ex
jasenka [17]

Answer:

95% confidence interval for the mean efficiency is [84.483 , 85.517].

Step-by-step explanation:

We are given that in a sample of 60 electric motors, the average efficiency (in percent) was 85 and the standard deviation was 2.

So, the pivotal quantity for 95% confidence interval for the population mean efficiency is given by;

          P.Q. = \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, \mu = sample average efficiency = 85

            \sigma = sample standard deviation = 2

            n = sample of motors = 60

            \mu = population mean efficiency

<em>So, 95% confidence interval for the mean efficiency, </em>\mu<em> is ;</em>

P(-2.0009 < t_5_9 < 2.0009) = 0.95

P(-2.0009  < \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } < 2.0009 ) = 0.95

P( -2.0009  \times {\frac{s}{\sqrt{n} } < {\bar X - \mu} < 2.0009  \times {\frac{s}{\sqrt{n} } ) = 0.95

P( \bar X -2.0009  \times {\frac{s}{\sqrt{n} } < \mu < \bar X +2.0009  \times {\frac{s}{\sqrt{n} } ) = 0.95

<u>95% confidence interval for</u> \mu = [ \bar X -2.0009  \times {\frac{s}{\sqrt{n} } , \bar X +2.0009  \times {\frac{s}{\sqrt{n} } ]

                                                 = [ 85 -2.0009  \times {\frac{2}{\sqrt{60} } , 85 +2.0009  \times {\frac{2}{\sqrt{60} } ]

                                                 = [84.483 , 85.517]

Therefore, 95% confidence interval for the population mean efficiency is [84.483 , 85.517].

8 0
3 years ago
those are currency exchange rates 1 us dollar = 7.76 hk dollars 1 us dollar =1.47 nk dollars work out the value of 1000 hk dolla
Alik [6]

Answer: 1000 HK dollars has the same value as 188.15 NZ dollars.

Step-by-step explanation:

We know that:

1 US dollar = 7.76 HK dollars

1 US dollar = 1.46 NZ dollars.

We have 1000 HK dollars, and we want to know the value in NZ dollars.

First, let's rewrite the 1000 HK dollars in US dollars.

Here we use the relation:

1 US dollar = 7.76 HK dollars

Then:

1 = (1 US dollar/7.76 HK dollars)

Then we can write:

1000 HK = (1000 HK)*1 = (1000 HK)*( (1 US /7.76 HK ))

1000 HK = (1000 HK/7.76 HK)* 1 US = 128.87 US

1000 HK  = 128.87 US

Now we can use the relationship:

1 US =  1.46 NZ

Then:

1 = (1.46 NZ)/(1 US)

So we can rewrite:

128.87 US = (128.87 US)*1 = (128.87 US)*( (1.46 NZ)/(1 US))

128.87 US = (128.87 US/1 US)*1.46 NZ = 188.15 NZ

Then:

1000 HK = 128.87 US = 188.15 NZ

So we can conclude that 1000 HK dollars has the same value as 188.15 NZ dollars.

5 0
3 years ago
Korey completely covered a square counter top using 103.5 ft² of tile without any overlap. Which measurement is closest to the s
kaheart [24]

Answer:

d

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
If f(x) is a function and f(1) = 5, then which of the following could not be true?
Natasha_Volkova [10]
It can't be f(1) = 1 because a function can't have two images on the same x.
8 0
3 years ago
Read 2 more answers
Jeannie is an experienced business traveler, often traveling back and forth from San Francisco to the East Coast several times p
lesya692 [45]

Answer:

The probability that Jeannie will miss her flight because her total time for catching her plane exceeds one hour is 0.0026.

Jeannie should leave her office 55 minutes early.

Step-by-step explanation:

Let <em>X</em> = time it requires Jeannie to catch her plane.

The random variable <em>X</em> is normally distributed, N(46, 5).

Compute the probability that Jeannie will miss her flight because her total time for catching her plane exceeds one hour as follows:

P(X>60)=P(\frac{X-\mu}{\sigma} >\frac{60-46}{5} )\\=P(Z>2.8)\\=1-P(Z

The probability that Jeannie will miss her flight because her total time for catching her plane exceeds one hour is 0.0026.

Now, it is provided that Jeannie has 96% chance of catching her flight if she reaches under <em>x</em> minutes.

That is, P (X < x) = 0.96.

Compute the value of <em>x</em> as follows:

P(X

**Use the <em>z</em>-table to compute the value of <em>z</em>.

The value of <em>z</em> is 1.751.

Compute the value of <em>x</em> as follows:

z=\frac{x-46}{5}\\ 1.751=\frac{x-46}{5}\\x=46+(1.751\times5)\\=54.755\\\approx 55

Thus, Jeannie should leave her office 55 minutes early.

4 0
3 years ago
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