22/25 i believe... i hope this helps
<u>(x-5)²+(y-5)²=36</u>
Answer:
Solution given:
radius [r]=6 units
centre[h,k]=(5,4)
we have
the equation of a circle is;
(x-h)²+(y-k)²=r²
(x-5)²+(y-5)²=6²
<u>(</u><u>x-5</u><u>)</u><u>²</u><u>+</u><u>(</u><u>y-5</u><u>)</u><u>²</u><u>=</u><u>3</u><u>6</u><u> </u><u>is</u><u> </u><u>a</u><u> </u><u>required</u><u> </u><u>equation</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>circle</u><u>.</u>
Answer:
2nd number = 13
First number = 15
3rd number = 30
Step-by-step explanation:
Let
2nd number = 1/2x - 2
First number = 1/2x
3rd number = x
Total = 58
x + 1/2x + 1/2x - 2 = 58
x + x+x/2 = 58 + 2
x + 2/2x = 60
x + x = 60
2x = 60
x = 60/2
= 30
x = 30
2nd number = 1/2x - 2
= 1/2*30 - 2
= 15 - 2
= 13
First number = 1/2x
= 1/2*30
= 15
3rd number = x
= 30
3x+2=x+2x+4
-2 -2
3x=x+2x+4-2
3x=3x+4-2
-3x -3x
x= 4-2
x=2
Answer:
32.99/4 is about 8.25
8.25 x 3= 24.75
about 24.75
Step-by-step explanation: