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3 years ago

What is the 4th term of the sequence?

Mathematics

1 answer:

matrenka [14]3 years ago

4 0

$\bf \begin{array}{ll}
term&value\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
a_1&8\\\\
a_2&6+a_{2-1}\\
&6+a_1\\
&6+8\\
&14\\\\
3&6+a_{3-1}\\
&6+a_2\\
&6+14\\
&20\\\\
a_4&6+a_{4-1}\\
&6+a_3\\
&6+20
\end{array}$

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According to Greek mathematician Zeno, if each bounce of a ball is half the height of the bounce before it,the ball will never s

vovikov84 [41]

From the diagram associated with this question it can be seen that the first bounce was 1 units high, thus the second bounce is 1 / 2 = 0.5 units high and the third bounce is 0.5 / 2 = 0.25 = 1/4 units high.

Given that B represents the second bounce and C represents the first bounce, the <span>fractions in hundredths that should be written at points B is 0.50 while at point C is 0.25</span>

8 0

3 years ago

What 2 numbers add to get 2 and multiply to 4

rusak2 [61]

Factor 4
4=1 times 4
2 times 2
they don't add to 2
set up equation
x+y=2
xy=4

first equation, subtract x from both sides
y=2-x
subsitute for y
x(2-x)=4
distribute
2x-x^2=4
add x^2
2x=x^2+4
subtract 2x
0=x^2-2x+4
use quadratic formula which is
if you have ax^2+bx+c=0 then
x= $\frac{ -b+/-\sqrt{b^{2}-4ac} }{2a}$ so

1x^2-2x+4=0
a=1
b=-2
c=4
x= $\frac{ -(-2)+/-\sqrt{(-2)^{2}-4(1)(4)} }{2(1)}$
x= $\frac{ 2+/-\sqrt{4-16} }{2}$
x= $\frac{ 2+/-\sqrt{-12} }{2}$
we have $\sqrt{-12}$ and that doesn't give a real solution
therefor there are no real solutions
but if you want to solve fully
x= $\frac{ 2+/-2\sqrt{-3} }{2}$
i= $\sqrt{-1}$
x= $\frac{ 2+/-2i\sqrt{3} }{2}$
x= $1+/-i\sqrt{3}$
x= $1-i\sqrt{3}$ or x= $1+i\sqrt{3}$ (those are the 2 numbers)

6 0

4 years ago

The bases of a right prism are isosceles trapezoids with bases of 10 ft and 18 ft

likoan [24]

Answer:

540 ft^2.

Step-by-step explanation:

The area of the trapezoid = h/2 (10 + 18) = 14h.

By Pythagoras the height h = √(5^2 - 4^2) = 3.

So the area of the 2 trapezoidal bases = 2 * 14*3

= 84 ft^2.

Now we calculate the area of the four lateral rectangular sides:

= 10*12 + 18*12 + 2*5*12

= 456 ft^2.

Total area = 456 + 54

= 540 ft^2.

4 0

3 years ago

Which of these four sets of side lengths will form a right trangle?

Mrac [35]

answer:

set 4

Step-by-step explanation:

because when you divide the numbers 12,16 and 20 by 2 you'll get 6,8 and 10 which is a Pythagoras family....and it will form a right angle triangle

4 0

2 years ago

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zmey [24]

Answer:

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3 0

3 years ago