It is a 40.5% increase, how I got my answer.
It is really simple, all I done was added $2,990 and on a caculater started at 100% increase would be 5,980, the reason I started out with 100% is because it is much easyer to judge how much I need to go down or up in percentage, so I knew that I needed to find $4,200, so I moved it down to 45% which equaled $4,335.5 so I brought it down to 41% which equals $4,215.9, so I brought it down to 40% which equals $4,186, then I brought it up to 40.5% which equals $4,200.95, but the .95 does not matter.
I hope this helps!
Answer:
383
Step-by-step explanation:
Apply the rule of BIDMAS,
Firstly, solve the problem in brackets;
(382+417)−416
799-416
383
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Answer:
22 millimeters
Step-by-step explanation:
Given that:
Scale of drawing = 11 millimeters : 4 meters
This means 4 meters of actual is represented as 11 millimeters on the drawing
If actual length of dining room = 8 meters ;
Lenght of dinning room in drawing will be x :
11 millimeters = 4 meters
X millimeters = 8 meters
Cross multiply :
4*x = 11 * 8
4x = 88
x = 88/4
x = 22
Hence, the length of the drawing will be 22 millimeters
Answer:
I: 82.1
Step-by-step explanation:
Answer:
option D
Step-by-step explanation:
![f(x) = x^2 + 5x + 6](https://tex.z-dn.net/?f=f%28x%29%20%3D%20x%5E2%20%2B%205x%20%2B%206)
![g(x)= \frac{1}{x+3}](https://tex.z-dn.net/?f=g%28x%29%3D%20%5Cfrac%7B1%7D%7Bx%2B3%7D)
(fog)(x) = f(g(x))
Plug in g(x) in f(x)
We plug in 1/x+3 in the place of x in f(x)
![f(g(x))= f(\frac{1}{x+3})= (\frac{1}{x+3})^2 + 5(\frac{1}{x+3}) + 6](https://tex.z-dn.net/?f=f%28g%28x%29%29%3D%20f%28%5Cfrac%7B1%7D%7Bx%2B3%7D%29%3D%20%28%5Cfrac%7B1%7D%7Bx%2B3%7D%29%5E2%20%2B%205%28%5Cfrac%7B1%7D%7Bx%2B3%7D%29%20%2B%206)
To simplify it we take LCD
LCD is (x+3)(x+3)
![\frac{1}{(x+3)(x+3)}+5\frac{1*(x+3)}{(x+3)(x+3)}+\frac{6(x+3)(x+3)}{(x+3)(x+3)}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%28x%2B3%29%28x%2B3%29%7D%2B5%5Cfrac%7B1%2A%28x%2B3%29%7D%7B%28x%2B3%29%28x%2B3%29%7D%2B%5Cfrac%7B6%28x%2B3%29%28x%2B3%29%7D%7B%28x%2B3%29%28x%2B3%29%7D)
![\frac{1}{x^2+6x+9}+\frac{(5x+15)}{x^2+6x+9}+\frac{6x^2+36x+54}{x^2+6x+9}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bx%5E2%2B6x%2B9%7D%2B%5Cfrac%7B%285x%2B15%29%7D%7Bx%5E2%2B6x%2B9%7D%2B%5Cfrac%7B6x%5E2%2B36x%2B54%7D%7Bx%5E2%2B6x%2B9%7D)
All the denominators are same so we combine the numerators
![\frac{1+5x+15+6x^2+36x+54}{x^2+6x+9}](https://tex.z-dn.net/?f=%5Cfrac%7B1%2B5x%2B15%2B6x%5E2%2B36x%2B54%7D%7Bx%5E2%2B6x%2B9%7D)
![\frac{6x^2+41x+70}{x^2+6x+9}](https://tex.z-dn.net/?f=%5Cfrac%7B6x%5E2%2B41x%2B70%7D%7Bx%5E2%2B6x%2B9%7D)
Option D is correct