C.budget for fixed expenses before flexiable expenses
I will write a very short story, so I hope this helps a little
The processing of gold: A diary entry
April 5/2018
I am the worlds most precious metal.
I am worth more than any silly diamond, and far more stronger than Iron. No one can come close to being as important as I.
I start as a tiny mineral, found underground where I spend my days perfecting myself. Most might find relatives of mine in water, buried among sand and dirt. Then we are put through the most rigorous of training until we are god.
Well, gold, but you know what I mean.
Once I am perfection, I will be sold among the masses of people. I will be loved my all and crafted into everything. If I wanted, I could take over the world...a world of just gold, wouldn't that be magical?
Today I think I will be made into a ring, I hope I am not squeezed on some fat woman's finger.
I hope this helps a little, Cheers :)
Answer:
b. will be lower if consumers perceive mobile phones to be a necessity.
Explanation:
The price elasticity of demand is described as the percentage variation in the demanded quantity of service or goods divided by the change in the percentage of the price. And henceforth it describes the responsiveness of the demanded quantity to a price change. And now if the mobile phones are thought of as being the necessity then the price will increase as demand will increase, and hence the price elasticity of demand will be lower. And if there is an improvement in the production technology then the price will be lowered, and hence price elasticity of demand will be less as the change in the percentage of the price will be negative. And the exact definition of it as we have described above. Hence, b is correct options.
Answer:
Option 1: May crash at runtime because it can input more elements than the array can hold
Explanation:
Given the code as follows:
- int[] a = {1, 3, 7, 0, 0, 0};
- int size = 3, capacity = 6;
- int value = cin.nextInt();
- while (value > 0)
- {
- a[size] = value;
- size++;
- value = cin.nextInt();
- }
From the code above, we know the <em>a</em> is an array with six elements (Line 1). Since the array has been initialized with six elements, the capacity of the array cannot be altered in later stage.
However, a while loop is created to keep prompting for user input an integer and overwrite the value in the array started from index 3 (Line 4- 9). In every round of loop, the index is incremented by 1 (Line 7). If the user input for variable <em>value</em> is always above zero, the while loop will persist. This may reach a point where the index value is out of bound and crash the program. Please note the maximum index value for the array is supposedly be 5.
Answer:
Please see the attached image
Explanation:
