Calculate the following absolute value |-1-1+2|-|-1+2|-|-2|

Solve the formula for the specified variable.

iragen [17]

D is the correct answer

7 0

2 years ago

Linear or non linear help

Olenka [21]

It should be nonlinear, nonlinear, linear

8 0

3 years ago

The graph of y > 1 2 x - 2 is shown. Which set contains only points that satisfy the inequality? A) {(6, 1), (-1, -3), (4, 4)

Kaylis [27]

Answer:

Option B) {(1, -1), (-3, -3), (2, 4)}

Step-by-step explanation:

The correct inequality is

$y>\frac{1}{2}x-2$

The solution of the inequality is the shaded area above the dashed line $y=\frac{1}{2}x-2$

see the attached figure to better understand the problem

we know that

If a ordered pair satisfy the inequality, then the ordered pair must lie in the shaded area of the solution

Verify each case

case A) {(6, 1), (-1, -3), (4, 4)}

ordered pair (6,1)

For x=6, y=1

substitute in the inequality

$1>\frac{1}{2}(6)-2$

$1>1$ ---> is not true

therefore

The point not satisfy the inequality

case B) {(1, -1), (-3, -3), (2, 4)}

ordered pair (1,-1)

For x=1, y=-1

substitute in the inequality

$-1>\frac{1}{2}(1)-2$

$-1>-1.5$ ---> is true

so

The point satisfy the inequality

ordered pair (-3,3)

For x=-3, y=3

substitute in the inequality

$3>\frac{1}{2}(-3)-2$

$3>-3.5$ ---> is true

so

The point satisfy the inequality

ordered pair (2,4)

For x=2, y=4

substitute in the inequality

$4>\frac{1}{2}(2)-2$

$4>-1$ ---> is true

so

The point satisfy the inequality

therefore

The set contains only points that satisfy the inequality

case C) {(1, -1), (-3, -3), (4, -2)}

ordered pair (4,-2)

For x=4, y=-2

substitute in the inequality

$-2>\frac{1}{2}(4)-2$

$-2>0$ ---> is not true

therefore

The point not satisfy the inequality

case D) {(-1, -3), (-3, -3), (2, 4)}

ordered pair (-1,-3)

For x=-1, y=-3

substitute in the inequality

$-3>\frac{1}{2}(-1)-2$

$-3>-2.5$ ---> is not true

therefore

The point not satisfy the inequality

4 0

3 years ago

Prove that there is only one circle determined by three noncollinear points

tensa zangetsu [6.8K]

Answer:

O lies on the perpendicular bisector of AB. ... Then, O' will lie on the perpendicular bisector PQ and RS. We know that, two lines cannot intersect at more than one point, So O' must coincide with O. Hence, there is one and only one circle passing through three non collinear points

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

If the Revenue for the week is $2000, and labor cost consists of two workers earning $8 per hour who work 40 hours each, what is

slega [8]

So,

All you have to do is find the total labor cost and put it over the revenue.

We have two workers each earning $8/hr. (lousy), and they work 40 hrs./week.

2 * $8 = $16/hr.

$16/hr. * 40 hrs. = $640

$\frac{640}{2000}$

Cross out zeros.
$\frac{64}{200}$

Simplify.
$\frac{2^6}{2^35^2}$
$\frac{2^3}{5^2}$
$\frac{8}{25}$

Convert the denominator to 100.
$\frac{8}{25} * \frac{4}{4} = \frac{32}{100}$
$\frac{32}{100}$
=
32%

The labor cost is 32% of the revenue.

7 0

3 years ago