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Verdich [7]
3 years ago
9

Find the volume of each figure. Round the answer 5 min 4 mm 18 nm 8 mm

Mathematics
1 answer:
valentina_108 [34]3 years ago
8 0
Try 18mm that should be the answer
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The equation y=5x represents the total cost, y, of buying x donuts at Store 1. The graph shows the total cost, y, of buying x do
Sidana [21]

what graph? I don't see one

3 0
3 years ago
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Complete all 3 questions.
nalin [4]

Answer:

1.x^2-5x

2.2x^2+15x+18

3. x^2+20x+18

Step-by-step explanation:

1.  x(x-5) x*x-5*x = x^2-5x

2. (x+6)(2x+3) x*2x+x*3+6*2x+6*3= 2x^2+15x+18

3.(2x^2+15x+18)-(x^2-5x)=x^2+20x+18

3 0
3 years ago
Would someone explain this
Romashka [77]

The answer is C 3n+2

3 0
4 years ago
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Find the fifth roots of 32(cos 280° + i sin 280°)
shusha [124]

Answer:

The fifth root is 2[cos(56°) + i sin(56°)]

Step-by-step explanation:

* To solve this problem we must revise De Moiver's rule

- In the complex number with polar form

∵ z = r(cosФ + i sinФ)

∴ z^n = r^n(cos(nФ) + i sin(nФ))

* In the problem

- The fifth root means z^(1/5)

- We can put 32 as a form a^n

∵ 32 = 2 × 2 × 2 × 2 × 2 = 2^5

∴ z = 2^5[cos(280°) + i sin(280°)]

* Lets find z^(1/5)

*z^{\frac{1}{5}}=[2^{5}]^{\frac{1}{5} } (cos(\frac{1}{5})(280)+isin(\frac{1}{5})(280)

*(2^{5})^{\frac{1}{5}}=2^{5.\frac{1}{5}}=2

∴ z^(1/5) = 2[cos(56) + i sin(56)]

* The fifth root of 32[cos(280°) + i sin(280°)] is 2[cos(56°) + i sin(56°)]

 

4 0
3 years ago
B2-4ac<br> When:<br> a=2<br> b=5<br> C=0
Vera_Pavlovna [14]

Answer: 10

Step-by-step explanation:

5*2-4*2*0

10-0

10

8 0
3 years ago
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